The correct answer is $40,000.
32,000 = 80% of 40,000
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
What do you mean doubling? You can add 7+7+7 which equals 21.
Answer:
= 29.82 yards/second
Step-by-step explanation:
The speed is given in the problem. We just need to convert its units. The multiplicative identity (that is, 1) may be used to change the units without changing the value. (note: do you know what the additive identity is?)
61 miles per hour
(61 miles) / (1 hour)
(61 miles)/(1 hour)*1
((61 miles)/(1 hour))*((5280 feet)/(1 mile))
((61 miles)/(1 hour))*((5280 feet)/(1 mile))*((1 yard)/(3 feet))*((1 hour)/(60 minutes))*((1 minute)/(60 seconds))
note: miles, feet, hours, minutes cancel out; leaving yards per second
(61/1)*(5280/1)*(1/3)*(1/60)*(1/60) yards/second (note: I write that way to paste into Excel)
60 women, 45 women, 20 women, 5women ,
