Answer:
1.) There are 16 juniors and 8 seniors in the Chess Club. If the club members decide to send 9 juniors to a tournament, how many different possibilities are there?
(16 over 9) = 16!/(9!*7!) = 11440
2.) How many different ways can 3 cards be drawn from a deck of 52 cards without replacement?
52*51*50 = 132600
3.) How many different ways can 3 cards be drawn from a deck of 52 cards with replacement?
52^3 = 140608
4.) A corporation has 5 officers to choose from which 3 are selected to comprise the board of directors. How many combinations are there?
(5 over 3) = 5!/(3! * 2!) = 10
5.) A combination lock has the numbers 1 to 40 on each of three consecutive tumblers. What is the probability of opening the lock in ten tries?
10/40^3 = 1/6400
D...........................
Answer:
A. f(x) = 6x + 9
Step-by-step explanation:
The given equation is:
y - 6x - 9 = 0
We have to write this equation in function notation with x as the independent variable. This means that y will be replaced by f(x) and all other terms will be carried to the other side of the equation to get the desired function notation.
y - 6x - 9 = 0
y = 6x + 9
f(x) = 6x + 9
Therefore, option A gives the correct answer.
If there were 30 Girls, 4 Girls played for each part.
A: the outlier would be 7500 because it is not as close to the other prices
