We know that
[area old square]=x*x--------> x²
[area new square]=(x+6)*(x+6)-------> (x+6)²-----> A=x²+12x+36
the answer is
An <span>expression to represent the area of the new square is (</span>x²+12x+36)
Answer:
Negative. Negative numbers don't have real square roots since a square is either positive or 0. The square roots of numbers that are not a perfect square are members of the irrational numbers
Y =
![3\sqrt[3]{3}](https://tex.z-dn.net/?f=%203%5Csqrt%5B3%5D%7B3%7D%20)
81 is the same as 3 x 3 x 3 x 3. Therefore we can take out three of the four 3s and leave one inside the cube root radical.
D) 1 1/4
She needs 1/4 to make 1 batch so multiply that by 5 (or add 1/4, 5 times) 5 * 1/4 = 5/4 = 1 1/4
FIND GCF!
3: 3, 6, 9, 12 ,15
4: 4, 8 , 12, 16