IT WOULD BE "D" I BELIEVE
HOPE IM RIGHT AND THIS HELPS
By concepts of polynomials and systems of linear equations, the constants c and d of the expression p(x) = x⁴ - 5 · x³ - 7 · x² + c · x + d are 29 and 30.
<h3>How to determine the missing coefficients of a quartic equation</h3>
A value x is a root of a polynomial if and only if p(x) = 0. We must replace the given equation with the given roots and solve the resulting system of <em>linear</em> equations:
(- 1)⁴ - 5 · (- 1)³ - 7 · (- 1)² + (- 1) · c + d = 0
- c + d = 1 (1)
3⁴ - 5 · 3³ - 7 · 3² + 3 · c + d = 0
3 · c + d = 117 (2)
The solution of this system is c = 29 and d = 30.
By concepts of polynomials and systems of linear equations, the constants c and d of the expression p(x) = x⁴ - 5 · x³ - 7 · x² + c · x + d are 29 and 30.
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The mass is 15 and can you speak english.
Answer:
9. x=-6, y=0
10. x=-9, y=-10
11. x=3, y=-1
Step-by-step explanation:
Multiply the first equation by 2.
Add the equations.
We figured out x now we have to figure out y. To figure out y plug in x into any equation.
Your answer is x = -6 and y = 0 for number nine.
Change the signs of the second equation becuase 3y and 3y are both positive. We need one of them to be negative.
Add them.
Now we have to figure out y.
x=-9 and y=-10 is your answer to number ten.
x=3 and y=-1 is the answer to number eleven. I hope this helps! Let me know if I got anything wrong.
