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Talja [164]
3 years ago
10

How do you take the derivative of 3x2 + x4?

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0
I suppose there was x²

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PLEASE IVE POSTED THIS FOUR TIMES CAN SOMEONE PLEASE HELP ME WRITE AN EQUATION FOR THIS! I GIVE BRAINLIST!
borishaifa [10]

Answer:

y= -2/3x-3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve the simultaneous equations
NeTakaya

Answer:

y = 2, x = -1

Step-by-step explanation:

2y - 5x = 9

2y = 9+5x

y = (9+5x) /2

4y + 3x = 5

4((9+5x) /2) + 3x = 5

13x + 18 = 5

13x = -13

x = -1

y = (9+5x) /2

y = (9+5(-1)) /2

y = 2

4 0
3 years ago
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If a translation maps ∠D onto ∠B, which of the following statements is true? triangle CAB, point E is on segment AC between poin
mrs_skeptik [129]

Answer:

The correct option is;

ΔCED ~ ΔCAB

Step-by-step explanation:

Given that the translation maps angle ∠D to angle ∠B, we have;

Angle ∠D is congruent to ∠B (Given)

Segment ED is parallel to segment AB (lines having similar angles to a common transversal)

Therefore, ∠A is congruent to ∠E, (Angle on the same side of a transversal to two parallel lines)

∠C is congruent to ∠C reflexive property

Therefore, we have;

∠C ≅ ∠C

∠E ≅ ∠A  

∠D ≅ ∠B

Which gives ΔCED is similar to ΔCAB (not ΔCBA)

4 0
3 years ago
6. An urn contains 15 red balls and 8 blue balls. In each draw, one ball is extracted at random. It is then returned to the urn,
Leviafan [203]

Answer:

P(C4) = 0.0711

Step-by-step explanation:

consider the first draw = 15/23  since it cannot be a blue ball

The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn

the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn

therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41

Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41

P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )

= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711

8 0
3 years ago
To order tickets online to a hockey game, there is a processing fee plus the cost per ticket. The cost for 5 tickets is $174.45.
xeze [42]
Wouldn’t the total for 13 tickets be $446.40 ? We already know the cost for 5 and 8 just add it up .... js
3 0
3 years ago
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