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3 years ago

13

Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range. y = negative 5 x s

quared + 3 x + 10

2 answers:

nadya68 [22]3 years ago

7 0

Answer:

Use a graphing calc.

Domain: All real numbers

Range: (negative infinity, 10.45]

Step-by-step explanation:

KengaRu [80]3 years ago

6 0

Answer:

Use a graphing calc.

Domain: All real numbers

Range: (negative infinity, 10.45]

Step-by-step explanation:

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Are the solutions of the equation x^4+3x^2+2=0 help

alex41 [277]

$x^4+3x^2+2=0\\\\\text{substitute}\ x^2=t\\\\t^2+3t+2=0\\\\t^2+t+2t+2=0\\\\t(t+1)+2(t+1)=0\\\\(t+1)(t+2)=0\iff t+1=0\ \vee\ t+2=0\\\\t=-1\ \vee\ t=-2\\\\t=x^2\ \text{therefore}\\\\x^2=-1\ \vee\ x^2=-2\\\\x=\pm\sqrt{-1}\ \vee\ x=\pm\sqrt{-2}\\\\x=\pm i\ \vee\ x=\pm i\sqrt2$

5 0

3 years ago

Solve the equation. Round to the nearest hundredth. Show work.

denis-greek [22]

Answer:

Final answer is approx x=-0.66.

Step-by-step explanation:

Given equation is $5^{-2x-1}=4^{4x+3}$ .

Now we need to solve equation $5^{-2x-1}=4^{4x+3}$ and round to the nearest hundredth.

$5^{-2x-1}=4^{4x+3}$

$\log(5^{-2x-1})=\log(4^{4x+3})$

$(-2x-1)\log(5)=(4x+3)\log(4)$

$-2x \log(5)- \log(5)=4x \log(4)+3 \log(4)$

$-2x \log(5) -4x \log(4)=3 \log(4) +\log(5)$

$x=\frac{\left(3\log(4)+\log(5)\right)}{\left(-2\log(5)-4\log(4)\right)}$

Now use calculator to calculate log values, we get:

$x=-0.65817959094$

Round to the nearest hundredth.

Hence final answer is approx x=-0.66.

8 0

3 years ago

The steps used to solve the equation 4x + 3 = 15 for x are shown below.

Vlada [557]

Answer:

there's nothing in step 1

it's not clear enough

5 0

2 years ago

Solve 2x + 5y = 20; 3x - 10y = 37 by elimination. How do you do this? Thank-you!

mr Goodwill [35]

$\left\{\begin{array}{ccc}2x+5y=20&\text{multiply both sides by 2}\\3x-10y=37\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}4x+10y=40\\3x-10y=37\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad7x=77\qquad\text{divide both sides by 7}\\.\qquad\boxed{x=11}\\\\\text{Put the value of x to the first equation:}\\\\2(11)+5y=20\\\\22+5y=20\qquad\text{subtract 22 from both sides}\\\\5y=-2\qquad\text{divide both sides by 5}\\\\\boxed{y=-\dfrac{2}{5}}\\\\Answer:\ \boxed{x=11\ and\ y=-\dfrac{2}{5}}$

6 0

2 years ago

Answers and work for answers please

larisa [96]

Answer:

1) 5 2) 6 3) 1.25 or -1.75

Step-by-step explanation:

1. x^2 - 25 = 0

x^2 - 25 = 0

First, add 25 to both sides!

x^2 = 25

Now square root both sides.

x = 5

2. (x-2)^2 = 16

First, square root both sides.

(x-2) = 4

Add 2 on both sides.

(x) = 6

x = 6

3. Quadratic Formula = -b ± $\sqrt{b^{2}-4ac }$ / 2a

Substitute in:

-6 ± $\sqrt{7^{2} -4(2)(6)}$ / 2(2)

-6± $\sqrt{49 - 48}$ / 4

Both forms:

-6 + $\sqrt{1}$ / 4

5 / 4 = 1.25

Negative:

-6 - 1 / 4

-7 / 4 = -1.75

8 0

2 years ago