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finlep [7]
3 years ago
13

5x + 6(x - 2) - 8 (x - 3)

Mathematics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

The value of x=-4. The figure is also attached below.

Step-by-step explanation:

Considering the expression

5x + 6(x - 2) - 8 (x - 3)

If we have to find the vale of x, then

5x + 6(x - 2) - 8 (x - 3)=0

5x+6x-12-8\left(x-3\right)=0

5x+6x-12-8x+24=0

3x+12=0

\mathrm{Subtract\:}12\mathrm{\:from\:both\:sides}

3x+12-12=0-12

3x=-12

\mathrm{Divide\:both\:sides\:by\:}3

\frac{3x}{3}=\frac{-12}{3}

x=-4

Therefore, the value of x=-4. The figure is also attached below.

Keywords: equation

Learn more about equation solution from brainly.com/question/13678520

#learnwithBrainly

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How to do: -8(1-a)=-7-(1-3a)
Fiesta28 [93]

In this question, you're solving for a.

Solve for a:

-8(1 - a) =-7 -(1 - 3a)

<em>use the distributive property</em>

-8 + 8a = -7 -(1 - 3a)

-8 + 8a = -7 - 1 + 3a

<em>combine like terms</em>

-8 + 8a = -8 + 3a

<em>subtract 3a from both sides</em>

-8 + 5a = -8

<em>add 8 to both sides</em>

5a = 0

<em>divide both sides by 5</em>

a = 0

7 0
3 years ago
Alex runs on the track at school each weekday morning. If he runs 5.9 miles each day, about how much does he run every month?
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Now, since we know that 5.9 is the amount of miles per day, we need to determine how many miles per month.

Usually, there are 20 days...because of no weekdays

Multiply.

5.9 * 20 = 118

Final answer:- He runs 118 miles per month. 

3 0
3 years ago
Read 2 more answers
30 POINTS Alex runs 2/3 of a mile each day how many days does he need to run before he has to run a whole number of miles​
kolezko [41]

Two days and he would’ve ran 1 and 1/3

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3 years ago
A scientist makes $150,000 per year. She deposits 5% of her yearly income in a travel savings account. How much money should she
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Step-by-step explanation:

3 0
3 years ago
Factor the polynomial F(x) =x^3-x^2-4x+4 completely.
Norma-Jean [14]

Answer:

Step-by-step explanation:

PART 1:

Possible roots by noticing the coefficient of first term:

x = 1, -1

PART 2:

1 | 1  -1  -4   4

 <u>      1   0  -4</u>

   1   0  -4  0

The remainder is zero, hence one factor is (x-1)

PART 3:

x^3-x^2-4x+4=(x^2-4)(x-1)\\\\x^3-x^2-4x+4=(x+2)(x-2)(x-1)

PART 4:

f(x)=(x+2)(x-2)(x-1)\\\\=(x^2-4)(x-1)\\\\=x^3-4x-x^2+4\\\\=x^3-x^2-4x+4

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3 years ago
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