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mrs_skeptik [129]
3 years ago
8

Describe the end behavior of a ninth-degree polynomial with a negative leading coefficient

Mathematics
1 answer:
Degger [83]3 years ago
5 0

Given:

The degree of polynomial = 9

Leading coefficient is negative.

To find:

The end behavior of the polynomial.

Solution:

Let the polynomial be P(x).

We have,

Degree of polynomial = 9, which is odd.

Leading coefficient is negative.

If the degree of a polynomial is odd and leading coefficient is negative, then

P(x)\to \infty\text{ as }x\to -\infty

P(x)\to -\infty\text{ as }x\to \infty

Therefore, the end behavior of the given polynomial is P(x)\to \infty\text{ as }x\to -\infty,P(x)\to -\infty\text{ as }x\to \infty.

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getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.
blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies.  Half of celias candies is equal to 2/3 of emmas candies.  

They had a total of 105 candies altogether.  

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}

Hence, candies with celias and emmas is 60 and 45 respectively.

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3 years ago
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