Let the groups be A, B, C and D. Then
n(A ∩ B ∩ C ∩ D) = 1
n(A ∩ B ∩ C ∩ D') = 10 - 1 = 9
n(A ∩ B ∩ C' ∩ D) = 10 - 1 = 9
n(A ∩ B' ∩ C ∩ D) = 10 - 1 = 9
n(A' ∩ B ∩ C ∩ D) = 10 - 1 = 9
n(A ∩ B ∩ C' ∩ D') = 100 - 9 - 9 - 1 = 81
n(A ∩ B' ∩ C ∩ D') = 100 - 9 - 9 - 1 = 81
n(A' ∩ B ∩ C ∩ D') = 100 - 9 - 9 - 1 = 81
n(A' ∩ B ∩ C' ∩ D) = 100 - 9 - 9 - 1 = 81
n(A' ∩ B' ∩ C ∩ D) = 100 - 9 - 9 - 1 = 81
n(A ∩ B' ∩ C' ∩ D) = 100 - 9 - 9 - 1 = 81
n(A ∩ B' ∩ C' ∩ D') = 1000 - 81 - 81 - 81 - 9 - 9 - 9 - 1 = 729
n(A' ∩ B ∩ C' ∩ D') = 1000 - 81 - 81 - 81 - 9 - 9 - 9 - 1 = 729
n(A' ∩ B' ∩ C ∩ D') = 1000 - 81 - 81 - 81 - 9 - 9 - 9 - 1 = 729
n(A' ∩ B' ∩ C' ∩ D) = 1000 - 81 - 81 - 81 - 9 - 9 - 9 - 1 = 729
Thus, all together there are 4(729) + 6(81) + 4(9) + 1 = 2,916 + 486 + 36 + 1 = 3,439 members in the groups.
Therefore, there are all together 3,439 members in the groups.
Answer:
To find alternate exterior angles, look at that outside space for each crossed line, on different sides of the transversal.
Step-by-step explanation:
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Answer: 165 combination can be possible.
Step-by-step explanation:
Here, According to the question,
Different types of machines in the weight room in gym = 11
And, . Geoff has time to use only 3 of them this afternoon.
Therefore, total number of different combination of machine can geoff choose from to use
= 
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( because 
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2x+5=47, solve algebraically to find x, the answer
