Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
This is one way you could write out the steps
f(x) = -2x^2 - 5
f(2) = -2(2)^2 - 5
f(2) = -2(4) - 5
f(2) = -8 - 5
f(2) = -13
I think the answer is 59.000 B
Answer:
Step-by-step explanation:
eq. of any line withslope 1/6 is
y=1/6x+c
∵ it passes through (-2,7)
so 7=1/6(-2)+c
c=7+1/3=22/3
eq. of line is
y=1/6x+22/3
vertex form of a parabola
y= a(x-h)^2 +k
y =a(x--3)^2 +2
y = a(x+3)^2 +2
Choice B
