2•14 =28, 2• 270=540, 2•141=282, 2 is the GCF
Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
The answer is 2 be 8/16 is 2
Let x be the original position.
After the first play they gain 9 yards. The position can be represented by
x + 9
After the second play they lose 22 yards. The position can be represented by
x + 9 - 22 = x - 13
Therefore, in total they lost 13 yards.
Step-by-step explanation:
Sorry I cant get any more answers but I really hope that this helps