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3 years ago

How to solve 3/5+2/3

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

4 0

Step by step:
3/5 + 2/3
Get a common denominator:
3•3/5•3 + 5•2/3•5
9/15 + 10/15
Answer: 19/15
Hope this helps!

djyliett [7]3 years ago

3 0

Answer:

1 4 /15

Step-by-step explanation:

3/5 + 2/3

the first step is to get a common denominator, 15

3/5 * 3/3 + 2/3 * 5/5

9/15 + 10/15

19/15

new we need to change it to a mixed number

15 goes into 19 one time with 4 left over

1 4/15

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50 POINTS:A chess competition has eliminations each round. The table below shows the number of players in each of the first 5 ro

Ket [755]

Round (x) 1 2 3 4 5
Players f(x) 256 128 64 32 16

16-256 / 5 - 1 = -240/4 = -60

A.) −60; on average, there was a loss of 60 each round.

7 0

3 years ago

The length of the famed fred's fence is 5 more than twice it's width if the perimeter of the fence is 510 feet find the dimensio

Sveta_85 [38]

Answer:

83 1/3 ft wide
171 2/3 ft long

Step-by-step explanation:

Let w represent the width of the area. Then 2w+5 represents the length. The perimeter is twice the sum of length and width:

P = 2(L+W)

510 = 2(2w+5 +w) . . substitute given values

255 = 3w +5 . . . . . . divide by 2

250 = 3w . . . . . . . . . subtract 5

83 1/3 = w . . . . . . . . .divide by 3; the width of the area

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The fenced area is 83 1/3 ft wide and 171 2/3 ft long.

4 0

4 years ago

2/4 times 1/4 = m IN SIMPLEST FORM

rjkz [21]

Answer:

Step-by-step explanation:

2/4 × 1/4 = (2×1)/(4×4) = 2/16 = 1/8

5 0

3 years ago

Read 2 more answers

If f(x) = 3x - 5 and g(x) = x^2 - x what is the value of f(2/3)

9966 [12]

Answer:

x=5/3 hope i helped you

Step-by-step explanation:

7 0

3 years ago

Two different samples will be taken from the same population of test scores where the population mean and standard deviation are

Rom4ik [11]

Answer:

The sample consisting of 64 data values would give a greater precision.

Step-by-step explanation:

The width of a (1 - α)% confidence interval for population mean μ is:

$\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{n}}$

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (n).

That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.

Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.

The two sample sizes are:

n₁ = 25

n₂ = 64

The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.

Width for n = 25:

$\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\ [2\cdot z_{\alpha/2}\cdot \sigma]$

Width for n = 64:

$\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\ [2\cdot z_{\alpha/2}\cdot \sigma]$

Thus, the sample consisting of 64 data values would give a greater precision.

3 0

4 years ago