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3 years ago

A number increase by three is two more twice the number.find the number.

Mathematics

1 answer:

mixer [17]3 years ago

5 0

Answer:

Step-by-step explanation:

1 increased by 3=1+3=4

Twice of 1=1+1=2

4 is two more than 2.

Therefore, the number=1

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In timara math class there are, 12 boys and 15 girls which of the following in the ratio to boys and girls in timaras math class

tiny-mole [99]

Answer:

4:5

Step-by-step explanation:

If there are 12 boys and 15 girls, the ratio of boys to girls will be 12:15.

However, this can be simplified by dividing each number by 3. This can be done since both 12 and 15 are divisible by 3.

12:15

= 4:5

So, the ratio of boys to girls in Timara's class is 4:5

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3 years ago

The scatter plot below shows the change in the demand for a pair of jeans at a store as the price changes. The sales manager use

Arlecino [84]

Answer:

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Step-by-step explanation:

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3 years ago

What is the side length of a cube with a volume of 0.216 m3?

aksik [14]

｡☆✼★ ━━━━━━━━━━━━━━━ ☾

Cube root 0.216 to get your answer

(Note: This makes sense if you know the volume of a cube is the same value multiplied together 3 times)

The answer is option A 0.6 m

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4 years ago

Which statement about proportional relationships is false? A proportional relationship must graph as a line. A graph of a propor

natka813 [3]

Answer:

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4 0

3 years ago

Read 2 more answers

Preview Activity 3.5.1. A spherical balloon is being inflated at a constant rate of 20 cubic inches per second. How fast is the

ArbitrLikvidat [17]

Answer:

The radius is increasing at a rate of approximately 0.044 in/s when the diameter is 12 inches.

Because $\frac{dr}{dt}=\frac{5}{36\pi }>\frac{dr}{dt}=\frac{5}{64\pi }$ the radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Let $r$ be the radius, $d$ the diameter, and $V$ the volume of the spherical balloon.

We know $\frac{dV}{dt}=20 \:{in^3/s}$ and we want to find $\frac{dr}{dt}$

The volume of a spherical balloon is given by

$V=\frac{4}{3} \pi r^3$

Taking the derivative with respect of time of both sides gives

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

We now substitute the values we know and we solve for $\frac{dr}{dt}$ :

$d=2r\\\\r=\frac{d}{2}$

$r=\frac{12}{2}=6$

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}\\\\\frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2} \\\\\frac{dr}{dt}=\frac{20}{4\pi(6)^2 } =\frac{5}{36\pi }\approx 0.044$

The radius is increasing at a rate of approximately 0.044 in/s when the diameter is 12 inches.

When d = 16, r = 8 and $\frac{dr}{dt}$ is:

$\frac{dr}{dt}=\frac{20}{4\pi(8)^2}=\frac{5}{64\pi }\approx 0.025$

The radius is increasing at a rate of approximately 0.025 in/s when the diameter is 16 inches.

Because $\frac{dr}{dt}=\frac{5}{36\pi }>\frac{dr}{dt}=\frac{5}{64\pi }$ the radius is changing more rapidly when the diameter is 12 inches.

8 0

3 years ago

A number increase by three is two more twice the number.find the number.​

A number increase by three is two more twice the number.find the number.