Answer:
To determine what is the difference between "6 + A" and "6 x A", the logic of the proposed mathematical operations must be explained:
In "6 + A", the value A is added to the initial value 6. Thus, for example, if A were worth 10, to the initial value 6 10 units are added, with which the final value is 16.
In contrast, in "6 x A", the initial value 6 is multiplied by as many times as the value A indicates. Therefore, continuing with the value of A as 10, in this case 6 would be multiplied by 10 times, giving a final value of 60.
Answer:
Step-by-step explanation:
You don't specify what you're supposed to do, so I'll make an educated guess.
Given the sequence f(1) = 4, f(n) = f(n − 1) + 11, find the first 5 terms:
f(1) = 4
f(2) = f(2 - 1) + 11 = f(1) + 11 = 4 + 11 = 15
f(3) = f(2) + 11 = 15 + 11 = 26
f(4) = f(3) + 11 = 26 + 11 = 37
f(5) = 37 + 11 = 48
Answer:
g(x) = f(x) + 18
Step-by-step explanation:
Answer: ![\sqrt[3]{6n}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B6n%7D)
Step-by-step explanation:
We have the following expression:
Which can be written as follows:
Multiplying the exponents:
Writing in radical form we finally have the result:
