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2 years ago

Change 0.12 into a simplified fraction. Explain how you solved

Mathematics

2 answers:

katen-ka-za [31]2 years ago

8 0

3/25. first you put 12 hundreths over 100, 12/100, and divide each side by 4

Aleks04 [339]2 years ago

4 0

3/25 because you first start off with 12/100 then you simplify it to 3/25

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Which expression calculates the speed in meters per second of an object that travels a distance of 100 m every 20 s?

patriot [66]

Speed=distance/time so it would be 100/20

5 0

2 years ago

Read 2 more answers

Which of these story problem describes the sum 19 + (-12)? Check all that apply. Show your work to justify your answer.

MatroZZZ [7]

-19 + (-12) = 7

Remove Parentheses
( -a ) = -a

= 19 - 12
Subtract The Numbers
19-12 = 7

8 0

2 years ago

Coco needs 150mg of a medication that comes in tablets labelled 100mg each. How many tablets will you give her?

shtirl [24]

Answer:

1.5

Step-by-step explanation:

If 1 tablet is 100mg, and you need 150mg, we set up this equation:

Let x be the number of tablets Coco needs.

x = 150/100

x = 1.5

Therefore, you need 1.5 tablets for the medication.

7 0

1 year ago

Tonya and Leo each bought a cell phone at the same time. The trade-in values, in dollars, of the cell phones are modeled by the

Paha777 [63]

Answer:

The answer is Tonya's phone had the greater initial trade-in value.

Leo's phone decreases at an average rate slower than the trade in value of Tonya's phone.

Step-by-step explanation:

Given

Tonya

$f(x) = 490 * 0.88^x$

Leo

$x \to g(x)$

$0 \to 480$

$2 \to 360$

$4 \to 470$

Solving (a): The phone with greater initial value

The initial value is when x = 0. So, we have:

$f(x) = 490 * 0.88^x$

$f(0) = 490 * 0.88^0$

$f(0) = 490 * 1$

$f(0) = 490$

From Leo's table

$g(0) = 480$

By comparison;

$f(0) > g(0)$

i.e.

$490 > 480$

So: Tonya's had the greater initial trade-in value

Solving (b): The phone with lesser rate

An exponential function is:

$y = ab^x$

Where:

$b \to rate$

For Tonya

$b = 0.88$

For Leo, we have:

$(x_1,y_1) = (0,480)$

$(x_2,y_2) = (2,360)$

So, the equation becomes:

$y = ab^x$

$480 = ab^0$ and $360 = ab^2$

Solving $480 = ab^0$ , we have:

$480 = a * 1$

$480 = a$

$a= 480$

$360 = ab^2$ becomes

$360 = 480 * b^2$

Divide both sides by 480

$0.75 = b^2$

Take square roots

$0.87 = b$

$b=0.87$ -- Leo's rate

By comparison; Leo's rate is slower i.e. 0.87 < 0.88

6 0

2 years ago

A student was given the line y=2/3x-1 and the point (-7, 1/2) and asked to find an equation that went through the given point an

Colt1911 [192]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of y=2/3x-1 anyway?

$\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{7em}y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x-1 \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so, notice, "one of his mistakes" is that he used 3/2 as the slope, not -3/2.

so, we're really looking for a line whose slope is -3/2 and runs through (-7, 1/2).

$\bf (\stackrel{x_1}{-7}~,~\stackrel{y_1}{\frac{1}{2}})~\hspace{10em} slope = m\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\cfrac{1}{2}=-\cfrac{3}{2}[x-(-7)]\implies y-\cfrac{1}{2}=-\cfrac{3}{2}(x+7) \\\\\\ y-\cfrac{1}{2}=-\cfrac{3}{2}x-\cfrac{21}{2}\implies y=-\cfrac{3}{2}x-\cfrac{21}{2}+\cfrac{1}{2}\implies y=-\cfrac{3}{2}x-10$

3 0

2 years ago