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ad-work [718]
2 years ago
5

A grocery store buys items and then applies a markup of 70%. What is the retail price of item that originally costs $10?

Mathematics
2 answers:
True [87]2 years ago
7 0

Answer:

$17

Step-by-step explanation:

since your finding retail price u need to do 10×.7 and that would be 7 then and the 7 to 10

Neko [114]2 years ago
5 0
The retail price would be 17$.

You just take 70% of 10, which is 7, and add it on to the original cost.
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1 1/5 is 6% of what number?
Ksenya-84 [330]

Answer:

36.67

Step-by-step explanation:

11/5=2.2

let the unknown no be x

6% of x=2.2

6/100 * x = 2.2

6x = 2.2*100

x = 220/6

x= 36.67

7 0
3 years ago
Freemont Run Club surveyed a random sample of 30 members about their running habit. Of the members surveyed, 9 said that they ru
atroni [7]

Answer:

i think its 420

Step-by-step explanation:

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3 years ago
Daisy spent a total of $31 before tax on ice cream. the table below shows the different flavors she bought. a carton of strawber
notsponge [240]
The cost of 1 vanilla ice cream and 1 strawberry ice cream should total to $31. Since you only bought one of each flavor, you simply have to add their unit prices. 

Cost for 1 carton of strawberry ice cream + Cost for 1 carton of vanilla ice cream = Total Cost
Total Cost = s + v  --> this is the general equation

Since s = 1.5 + v, the modified equation would be
Total Cost = 1.5 + v + v
Total Cost = 1.5 + 2v
5 0
3 years ago
If x is a rational number and y is the opposite of x,why do x y have the same absolute value?
olga2289 [7]
They have the same absolute value because all opposites have the same absolut value because they both are the same distance from zero
5 0
3 years ago
Identify the interval on which the quadratic function is positive.
Alenkasestr [34]

Answer:

\textsf{1. \quad Solution:  $1 < x < 4$,\quad  Interval notation:  $(1, 4)$}

\textsf{2. \quad Solution:  $-2 < x < 4$,\quad  Interval notation:  $(-2, 4)$}

Step-by-step explanation:

<h3><u>Question 1</u></h3>

The intervals on which a <u>quadratic function</u> is positive are those intervals where the function is above the x-axis, i.e. where y > 0.

The zeros of the <u>quadratic function</u> are the points at which the parabola crosses the x-axis.  

As the given <u>quadratic function</u> has a negative leading coefficient, the parabola opens downwards.   Therefore, the interval on which y > 0 is between the zeros.

To find the zeros of the given <u>quadratic function</u>, substitute y = 0 and factor:

\begin{aligned}y&= 0\\\implies -7x^2+35x-28& = 0\\-7(x^2-5x+4)& = 0\\x^2-5x+4& = 0\\x^2-x-4x+4& = 0\\x(x-1)-4(x-1)&= 0\\(x-1)(x-4)& = 0\end{aligned}

Apply the <u>zero-product property</u>:

\implies x-1=0 \implies x=1

\implies x-4=0 \implies x=4

Therefore, the interval on which the function is positive is:

  • Solution:  1 < x < 4
  • Interval notation:  (1, 4)

<h3><u>Question 2</u></h3>

The intervals on which a <u>quadratic function</u> is negative are those intervals where the function is below the x-axis, i.e. where y < 0.

The zeros of the <u>quadratic function</u> are the points at which the parabola crosses the x-axis.  

As the given <u>quadratic function</u> has a positive leading coefficient, the parabola opens upwards.   Therefore, the interval on which y < 0 is between the zeros.

To find the zeros of the given <u>quadratic function</u>, substitute y = 0 and factor:

\begin{aligned}y&= 0\\\implies 2x^2-4x-16& = 0\\2(x^2-2x-8)& = 0\\x^2-2x-8& = 0\\x^2-4x+2-8& = 0\\x(x-4)+2(x-4)&= 0\\(x+2)(x-4)& = 0\end{aligned}

Apply the <u>zero-product property</u>:

\implies x+2=0 \implies x=-2

\implies x-4=0 \implies x=4

Therefore, the interval on which the function is negative is:

  • Solution:  -2 < x < 4
  • Interval notation:  (-2, 4)
3 0
1 year ago
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