Step 1: We make the assumption that 498 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=498$100%=498.
Step 4: In the same vein, $x\%=4$x%=4.
Step 5: This gives us a pair of simple equations:
$100\%=498(1)$100%=498(1).
$x\%=4(2)$x%=4(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{498}{4}$
100%
x%=
498
4
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{4}{498}$
x%
100%=
4
498
$\Rightarrow x=0.8\%$⇒x=0.8%
Therefore, $4$4 is $0.8\%$0.8% of $498$498.
Shifting to left mean adding the number from each occurrence of x from the given function.
So, shifting x³ , 3 units to left will result in:
f(x) = (x + 3)³
Shifting down means subtracting the number from the function value.
So, shifting 2 units down will result in:
f(x) = (x + 3)³ - 2
Therefore, option A is the correct graph
A) $15 ÷ 40% =
15×.4= 6
15+6= 21
B) $38 × .25=9.5
38-9.5=28.50
28.50×.06=1.71
28.50+1.17=30.21
I think this is how you do it. would wait for other answers as well to double check.
The correct answer is
the flagpole is <span>
33 feet high</span>.
Explanation:
Please refer to the attached picture.
We know:
CD = 40 feet
AC = 5 feet
∠BDC = α = 35°
Using trigonometry, we know that the definition of the tangent of an angle is the ratio between the opposite side and the adjacent side, therefore:
tan α = BC / CD
Solving for BC:
BC = CD · <span>tan α
= 40 </span>· tan (35)
= 28 feet
In order to find the height of the flagpole, we need to add the distance of the clinometer from the ground:
AB = BC + AC
= 28 + 5
= 33
Hence, the flagpole is
33 feet high.
Answer:
854/3
Step-by-step explanation:
Find the GCD (or HCF) of numerator and denominator
GCD of 1708 and 6 is 2
Divide both the numerator and denominator by the GCD
1708 ÷ 2
6 ÷ 2