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3 years ago

15

In the diagram below, what needs to be labeled in order to prove triangle AHL and triangle EML are congruent by the SSS postulat

e

1 answer:

Alekssandra [29.7K]3 years ago

3 0

Answer:

<em>Final answer is HL = LM.</em>

Step-by-step explanation:

We have been given a diagram having two triangles in which sides AH= EM and AL=EL.

Now we need to find which statement is missing to prove that triangles AHL and EML are congruent using SSS.

SSS means (side - side - side)

Two pair of equal sides are already given so we have completed SS of SSS.

Last "S" means we need one more pair of equal sides so that must be using remaining sides HL and LM

Hence final answer is HL = LM.

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Television networks frequently run public opinion polls on issues of concern. One network conducted a scientific poll asking a q

kobusy [5.1K]

Answer:

Option d

Step-by-step explanation:

Given that television networks frequently run public opinion polls on issues of concern. One network conducted a scientific poll asking a question concerning the approval rating of the way President Obama was handling the Iraq War. At about the same time a second network ran an online poll using a very similar question.

Observed data is

Poll Scien Online total

approve 339 385 724

disapprove 780 573 1363

1119 958 2087

$H_0: Both scientific and online are consistent\\H_a: not consistent$

(Two tailed chi square test)

Let us find out expected and chi square

Expected = row total x column total/grand total

The cell count expected in the online poll for those who approve

= $\frac{724*968}{2087} \\=333.94$

chi square = 7.81

Hence option d is right.

4 0

2 years ago

5/2.35 = x/12<br> what does x=

postnew [5]

Answer:

$x = \frac{60}{2.35}$ or $x = 25.531...$

Step-by-step explanation:

<u>Step 1: Cross Multiply</u>

<u /> $\frac{5}{2.35} = \frac{x}{12}$

$5(12) = 2.35(x)$

$60 = 2.35x$

<u>Step 2: Divide both sides by 2.35</u>

<u /> $60 / 2.35 = 2.35x / 2.35$

$x = \frac{60}{2.35}$ or $x = 25.531...$

Answer: $x = \frac{60}{2.35}$ or $x = 25.531...$

5 0

3 years ago

Love is patient, love is kind. It does not envy, it does not boast, it is not proud. It does not dishonor others, it is not self

Virty [35]

Answer:

Ok

Explanation:

Thank you for sharing :)

7 0

3 years ago

Read 2 more answers

What is 5/2(4x+8) in simplified form?

VikaD [51]

got u

Step-by-step explanation:

the answer is 10x+20

4 0

2 years ago

Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t

katrin2010 [14]

Answer:

$\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24$

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of $\triangle ACD$ and the hypotenuse of $\triangle ADB$ .

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

$\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}$

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is $\angle CAD$ . The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

$\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}$

Now use this value in the Law of Sines to find AD:

$\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}$

Recall that $\sin 45^{\circ}=\frac{\sqrt{2}}{2}$ and $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$ :

$AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}$

Now that we have the length of AD, we can find the length of AB. The right triangle $\triangle ADB$ is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio $x:x\sqrt{3}:2x$ , where $x$ is the side opposite to the 30 degree angle and $2x$ is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent $2x$ in this ratio and since AB is the side opposite to the 30 degree angle, it must represent $x$ in this ratio (Derive from basic trig for a right triangle and $\sin 30^{\circ}=\frac{1}{2}$ ).

Therefore, AB must be exactly half of AD:

$AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24$

3 0

2 years ago

Read 2 more answers