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Zielflug [23.3K]
3 years ago
14

Isabella belongs to a fitness club. She paid a initial fee of 50 when she joined and also pays 10 per month

Mathematics
2 answers:
Allushta [10]3 years ago
8 0

Answer:

The equation would be 10x+50

Step-by-step explanation:

Fynjy0 [20]3 years ago
8 0

Answer:

60 one month+10 each month

Step-by-step explanation:

you add 50

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Answer:

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Step-by-step explanation:

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3 0
2 years ago
2x + 3 + 4x + 8 = 3x - 10
vodomira [7]

\text {Hello! Let's solve this Equation!}

\text {Your First Step is to Simplify the Equation:}

\text {(2x+4x)+(8+3)}

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\text {6x+11-3x=3x-10-3x}\\\text {3x+11=-10}

\text {Next Step is to Subtract 11:}

\text {Q: Why Subtract 11?}

\text {A: So they cancel out. We cross them out once we subtract.}

\text {3x+11-11=-10-11}\\\text {3x=-21}

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8 0
3 years ago
George wants to buy pets for each of his 5 grandchildren if he buys 3 pooples and 2 cats he will spend 1200 if he buys 2 poodles
Gre4nikov [31]

Answer:

Each poodle = $300

Each Cat = $150

Step-by-step explanation:

Let number of poodles be P and number of cats be C

"if he buys 3 pooples and 2 cats he will spend 1200" mathematically:

3P + 2C = 1200-------eq 1

"2 poodles and 3 cats he will spend 1050" mathematically:

2P + 3C = 1050 ------eq 2

So now we have a system of 2 equations with 2 unknowns, we'll solve by elimination

eq 1 x 3 : 3 (3P + 2C) = 3  (1200)

9P + 6C = 3600 ------ eq 3

eq 2 x 2: 2(2P + 3C) = 2(1050)

4P + 6C = 2100---------eq 4

By elimination : eq 3 - eq 4

(9P + 6C) - (4P + 6C) = 3600 - 2100

9P - 4P = 1500

5P = 1500

P = 300  (answer)

Substituting back into eq 1

3(300) + 2C = 1200

900 + 2C = 1200

2C = 1200 - 900

2C = 300

C = 150(answer)

8 0
3 years ago
Find the difference.<br><br> Show your work<br><br> -3/4 - 4/3
myrzilka [38]

Answer:

-25/12

Step-by-step explanation:

I assume you want to subtract 4/3 from -3/4   OR   combine -3/4 and -4/3.

Here the LCD is (4)(3) = 12.

Then -3/4 becomes -9/12 and -4/3 becomes -16/12.  

Then -9/12 - 16/12 = -25/12

6 0
3 years ago
Which pair of equations when graphed has lines that are perpendicular?
MrRa [10]
B you can check on here https://www.algebra.com/algebra/homework/Graphs/Graphs.faq.question.78908.html
8 0
3 years ago
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