the length of a rectangle is 4 feet more than its width. The area of the rectangle is 60ft^2. Find the length and width of the r
ectangle.
1 answer:
Answer:
10 and 6
Step-by-step explanation:
Let A be the area of the rectangle, w the width and L the length
● A = w*L
The length is 4 feet more that the width so L = w+4
● A = w ×(w+4)
● A = w^2 + 4w
The area is 60 ft^2
● w^2 + 4w = 60
Substract 60 from both sides
● w^2 + 4w - 60 = 0
This a quadratic equation
We will solve it by graphing it
The solution are 6 and -10 since the graph intersect with the x-axis in those points (pictures below)
The width is 6 feet long since it is a distance and a distance is always positive.
● w = 6
● L = w + 4
● L = 6 + 4
● L = 10
The width is 6 feet and the length is 10 feet
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Answer:
Find the area of each room and add the areas
Step-by-step explanation:
Please find the full question in the attached image
the area of rectangle is length x breadth. The area of each room would be found and the three areas would be added together
for example ,
dimension of room 1 = 5 x 3
dimension of room 2 = 2 x 3
dimension of room 3 = 4 x 5
area of room 1 = 15
area of room 2 = 6
area of room 3 = 20
total area = 15 + 6 + 20 = 41
Answer:
53
Step-by-step explanation:
Let x be the number of children tickets sold and y be the number of adult tickets sold. Then
x+y=128.
The cost of x children tickets is $5.10x and the cost of y adult tickets is $9.70y, so
5.10x+9.70y =896.60.
From the first equation,
x=128-y,
then
53 adult tickets were sold.