Hey there!
(9) 2x-9y=45
... -9y=-2x+45
... y = (2/9)x - 5
Slope = 2/9
y-intercept = (0,-5)
(11) 3y+2x=-15
... 3y=-2x-15
... y = (-2/3)x - 5
Slope = -2/3
y-intercept = (0,-5)
(12) 10x+8y=40
... 8y=-10x+40
... y=(-10/8)x+5
Slope = -5/4 (after simplifying )
y-intercept = (0,5)
Hope my answer helps!
<u>Answer:</u>
The older repear will harvest in 6 hrs
<u>Explanation:</u>
Given a field can be harvested in 1 hr with 2 reapers
Consider the total field to be 1
Let x be the time of older’s reaper
The field can be harvested in 1.2 hr with newer reaper alone
Older’s time of harvesting =
per hour
Newer’s time of harvesting =
per hour
Total (Older+Newer) = 1 =
}


1.2 + x = 1.2x
1.2 = 0.2x
x = 6
Therefore, older repear will harvest in 6 hrs
The answer is the following:
4x(2x+3)
hope it helped :)
<h2>
The value of x "option A) 12.5" is required answer.</h2>
Step-by-step explanation:
In given figure,
Base (b) = 11 and Angle = 28°
To find, the value of x = ?
We know that,

Where, h is the hypotaneous = x
⇒ 
⇒ 
The value of
= 0.8829
⇒ x =
⇒ x = 12.458
⇒ x ≈ 12.5
∴ The value of x ≈ 12.5
Thus, the value of x "option A) 12.5" is required answer.
Answer:
Step-by-step explanation:
Hello
A (5;2)
B (-1;-7)
y = ax + b
2 = 5a + b
-7 = -a + b
2 - (-7) = 5a - (-a) + b - b
2 + 7 = 5a + a
9 = 6a
a = 9/6
a = 3/2
2 = 3/2 * 5 + b
b = 2 - 15/2
b = 4/2 - 15/2
b = 11/2
y = 3/2 x + 11/2
y+1= 3/2(x-4)
y + 1 = 3/2 x - 6
y = 3/2 x - 6 - 1
y = 3/2 x - 7 => no
y-4= 3/2(x+1)
y - 4 = 3/2 x + 3/2
y = 3/2 x + 3/2 + 4
y = 3/2 x + 3/2 + 8/2
y = 3/2 x + 11/2 => yes
y+4= 3/2(x-1)
y + 4 = 3/2 x - 3/2
y = 3/2 x - 3/2 - 4
y = 3/2 x - 3/2 - 8/2
y = 3/2 x - 11/2 => no
y-1= 3/2 (x+4)
y - 1 = 3/2 x + 6
y = 3/2 x + 6 + 1
y = 3/2 x + 7 => no