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4 years ago

Which statement is true about the function f(x)= StartRoot negative x EndRoot?

Mathematics

2 answers:

sveticcg [70]4 years ago

6 0

Because x is negative the domain of the function is all negative real numbers.

Set the radical greater than or equal to 0:

-x >= 0

Turn x positive by multiplying both sides by -1. When you multiply an inequality by -1 you need to reverse the inequality sign:

X <= 0

Domain is all real numbers below 0 so all negative real numbers.

just olya [345]4 years ago

6 0

Answer:

Because x is negative the domain of the function is all negative real numbers.

Set the radical greater than or equal to 0:

-x >= 0

Turn x positive by multiplying both sides by -1. When you multiply an inequality by -1 you need to reverse the inequality sign:

X <= 0

Domain is all real numbers below 0 so all negative real numbers.

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5 x (-4)-((-6)-7)<br> (The X means to multiply)

Sindrei [870]

Answer:

-20 - 42

-62

$\huge\underline\red{Hope\:that\:helps}$

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3 years ago

Read 2 more answers

20 POINTS! PLEASE SOMEONE HELP! I'LL GIVE YOU BRAINLIEST AND 5 STAR IF YOU ARE CORRECT!!

katrin2010 [14]

Answer:

a) -15, -8, -3.3, 8/9

Step-by-step explanation:

b) 8/9, -3.3(And I say its -3.3, because you need to write it in its original form.), so far its 8/9, -3.3, -8, -15.

c) Because the absolute value is the positive value of that number. (i.e, -3 is 3 places away from 0, so it's absolute value would be 3.)

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3 years ago

Equivalent Expression for 7[2r-3]

Anarel [89]

Answer:

7[2r-3].

Step-by-step explanation:

7[2r-3]

= 7*2r + 7 * -3

=7[2r-3]

6 0

4 years ago

sveticcg [70]

(a)The domain of the function is, $\rm x \geq -c^2 \ x\neq0$

(b)The given function is discontinuous at x=0.

<h3>What is the domain and range of a function?</h3>

Domain is the set of values for which the given function is defined. Range is the set of all values which the given function can output.

The standard function is;

$\rm f(x)= \frac{\sqrt{x+c^2-c} }{x} , c > 0$

The domain of the given function is found as;

$\rm x+c^2 \geq 0 \ x\neq 0 \\\\ x\geq-c^2 \ x\neq 0$

The domain of the function is,

$\rm x \geq -c^2 \ x\neq0$

To find the function is continuous or not, we have to find the continuity;

$\rm f(x) = \frac{\sqrt{ x+c^2-c}}{x} ,c > 0$

At x= 0 the function is undefined. So that the function is discontinuous at x=0.

Hence, The domain of the function is, $\rm x \geq -c^2 \ x\neq0$ and the function is discontinuous at x=0.

To learn more about domain, refer to the link:

brainly.com/question/20073127

#SPJ1

7 0

3 years ago

Simplify .<br> S + 3 -2- +7<br> z + - 5<br> 0<br> + +5<br> o y +5

Katena32 [7]

Answer:

5 1 2

---- x - ---- x + ---- y - 2 + 7

7 7 7

These are like terms so add and subtract:

4 2

---- x + ---- y + 5

7 7

6 0

3 years ago