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3 years ago

What is 42 divided by 6?

Mathematics

2 answers:

irakobra [83]3 years ago

6 0

42/6 is 7 because seven 6s go in 42

babunello [35]3 years ago

3 0

Answer:

Step-by-step explanation:

6 times 7 equals 42 so 42 divided by 6 equals 7

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yarga [219]

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3 years ago

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Is 5.8 greater then fifty eight hundreths

Korolek [52]

Answer:

Step-by-step explanation:

fifty eight hundreths= 5,800

5.8<5,800

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3 years ago

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(1 point)

marusya05 [52]

Answer:

The correct answer is: {2,4,6,8}

Step-by-step explanation:

Given sets are:

P = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9) and V= {2, 4, 6, 8, 10, 12, 14, 16, 18, 20)

We have to find

P∩V

The symbol is used for intersection of two sets. In intersection, only common elements of both sets are written in result.

So,

P∩V = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9) ∩ {2, 4, 6, 8, 10, 12, 14, 16, 18, 20)

P∩V = {2,4,6,8}

Hence,

The correct answer is: {2,4,6,8}

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3 years ago

GEOMETRY: Determine whether segment MN is parallel to segment KL. Justify your answer.

hichkok12 [17]

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3 years ago

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Assume that the helium porosity of coal samples taken from any particular seam is Normally distributed with true standard deviat

riadik2000 [5.3K]

Answer:

a) $4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

b) $4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

$4.56+2.33\frac{0.75}{\sqrt{16}}=4.99$

c) $n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55$

Step-by-step explanation:

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

Part b

$4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

$4.56+2.33\frac{0.75}{\sqrt{16}}=4.99$

Part c

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =0.4/2 =0.2 we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55$

5 0

3 years ago