First of all, the left triangle is an equilateral triangle. Which means that all the interior angles are 60 degrees.
4w=60
w=15
Then all 3 sides are equal thus we can set up equation 3x-y=4y then simplify,
3x=5y
Going to the triangle on the right its isosceles we can set up equation 2x+50=180
2x=130
x=75
Substitute this back into equation above 3x=5y
5y=3*75
y=45
Therefore
x=75
y=45
w=15
Done!
It has not been indicated whether the figure in the questions is a triangle or a quadrilateral. Irrespective of the shape, this can be solved. The two possible shapes and angles have been indicated in the attached image.
Now, from the information given we can infer that there is a line BD that cuts angle ABC in two parts: angle ABD and angle DBC
⇒ Angle ABC = Angle ABD + Angle DBC
Also, we know that angle ABC is 1 degree less than 3 times the angle ABD, and that angle DBC is 47 degree
Let angle ABD be x
⇒ Angle ABC = 3x-1
Also, Angle ABC = Angle ABD + Angle DBC
Substituting the values in the above equations
⇒ 3x-1 = x+47
⇒ 2x = 48
⇒ x = 24
So angle ABD = 24 degree, and angle ABC = 3(24)-1 = 71-1 = 71 degree
Answer:3/2
Step-by-step explanation:
Answer:
a 4th of a cup maybe
Step-by-step explanation: