3 years ago

The solution for y on problem y=11+4x

Mathematics

1 answer:

Ymorist [56]3 years ago

4 0

I think you are missing part of the problem. If you had another equation or a value for x you could solve it.

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Ill give u brainliest pls help

Alenkinab [10]

Answer:

It is answer A) 5x^8y^8z^3 (sq rt 2y)

Step-by-step explanation:

1. Factor out the perfect square

(sqr rt) 5^2 × 2x^16 × y^16 xyz^6

2. Split each factor to their own square root

3. Simplify these roots

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2 years ago

Read 2 more answers

Find the measurement of n please.

mezya [45]

I think it’s C if you still need an answer but don’t trust me on that

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2 years ago

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The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the

erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes is 0.4786.

Step-by-step explanation:

The random variable X is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, β = 19 minutes.

The random variable X follows an Exponential distribution with parameter $\lambda=\frac{1}{\beta}=\frac{1}{19}$ .

The probability distribution function of X is:

$f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...$

Compute the value of the event (X > 14) as follows:

$P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786$

Thus, the probability that the wait time is greater than 14 minutes is 0.4786.

7 0

2 years ago

In a race, 28 cyclists got a flat tire on their bikes. If it takes 2.5 minutes to repair each bicycle, how long did it take to r

alexgriva [62]

One hour and ten minutes

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3 years ago

1. SUNDAES Carmine bought 5 ice cream sundaes for his friends. If each sundae costs $4.95, how much did he

Soloha48 [4]

Answer:

24.75

Step-by-step explanation:

you want to multiply 4.95×5 and you will get the answer $24.75.

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2 years ago