Ask question

Ask question

All categories

3 years ago

6

I’m confused. List the following numbers in order from least to greatest. —1.4, 0.75, —2 1/3, 21%, 4/5

2 answers:

Anna007 [38]3 years ago

6 0

The answer is -21/3, -1.4, 21%, 4/5,0.75.

You have to convert them to the same unit.

joja [24]3 years ago

4 0

Answer:-1.4,72,28,28,28,82

Step-by-step explanation:

Because I did a random answer hjfjdkwkshfhdje

You might be interested in

PLEASE HELP PLEASE HELP

Yakvenalex [24]

Answer:

Option D - Line P

Step-by-step explanation:

Look at the coordinates in the (x, y) column of Max's table and see which line has the same points.

8 0

2 years ago

G es to prove that if a, b, and c are integers, where a ≠ 0 and c ≠ 0, such that ac | bc, then a |

Alex Ar [27]

$ac\mid bc$ means there exists an integer $n$ such that $ac=bcn$ . We can divide both sides by $c$ because $c\neq0$ . This implies $a=bn$ for some integer, which is identically $a\mid b$ .

3 0

3 years ago

Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 22 Pennies 27 Dimes 9 Nickels

kap26 [50]

Answer:

$P(Penny\ and\ Dime) = \frac{9}{116}$

Step-by-step explanation:

Given

$Pennies = 22$

$Dimes = 27$

$Nickels = 9$

$Quarters = 30$

Required

$P(Penny\ and\ Dime)$

This is calculated as:

$P(Penny\ and\ Dime) = P(Penny) * P(Dime)$

Since it is a selection without replacement, the computation is:

$P(Penny\ and\ Dime) = \frac{Penny}{Total} * \frac{Dime}{Total-1}$

So, we have:

$P(Penny\ and\ Dime) = \frac{22}{22+27+9+30} * \frac{Dime}{22+27+9+30-1}$

$P(Penny\ and\ Dime) = \frac{22}{88} * \frac{27}{87}$

$P(Penny\ and\ Dime) = \frac{1}{4} * \frac{9}{29}$

$P(Penny\ and\ Dime) = \frac{9}{116}$

5 0

2 years ago

Question 11 (Multiple Choice Worth 1 points

Diano4ka-milaya [45]

Answer:

$3\frac{4}{33}=3.\bar1\bar2$

Step-by-step explanation:

Given:

Simplify The given choice.

$3\frac{4}{33}=\frac{33\times 3 +4}{33}=\frac{99+4}{33}=\frac{103}{33}=3.1212121=3.\bar1\bar2$

$3\frac{8}{33}=\frac{33\times 3 +8}{33}=\frac{99+8}{33}=\frac{107}{33}=3.242424=3.\bar2\bar4$

$3\frac{10}{39}=\frac{39\times 3 +10}{39}=\frac{117+10}{39}=\frac{127}{39}=3.2564$

$3\frac{5}{39}=\frac{39\times 3 +5}{39}=\frac{117+5}{39}=\frac{122}{39}=3.12820$

Therefore, the first option $3\frac{4}{33}$ is correct.

4 0

3 years ago

Prove this <br><br> 1-tan^2x/1+tan^2x=cos^2x-sin^2x

tatiyna

Answer:

see explanation

Step-by-step explanation:

Using the identity

tan x = $\frac{sinx}{cosx}$

Consider the left side

$\frac{1-tan^2x}{1+tan^2x}$

= $\frac{1-\frac{sin^2x}{cos^2x} }{1+\frac{sin^2x}{cos^2x} }$ ( multiply numerator and denominator by cos²x to clear fractions

= $\frac{cos^2x-sin^2x}{cos^2x+sin^2x}$ ← ( cos²x + sin²x = 1 ]

= cos²x - sin²x

= right side , thus proven

7 0

2 years ago