Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
7
Step-by-step explanation:
Answer:
The 5 unknown are 1 quarter, 3 dimes, and 1 penny.
Answer:
because there is no cents, so its a whole number, and it will help if u put the answer choices
Step-by-step explanation:
Answer:
The answer is 1.5
Step-by-step explanation: