Answer:
a) 31.38%
b) 28.44%
c) 33.33%
d) 73.46%
e) 53.89%
Step-by-step explanation:
<h3>
(See picture attached for sub-totals)
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a) What is the probability of selecting a student whose favorite sport is skiing?
P = 171/545 = 0.3138 = 31.38%
b) What is the probability of selecting a 6th grade student?
P = 155/545 = 0.2844 = 28.44%
c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?
P = 70/210 = 0.3333 = 33.33%
d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?
P = 155/211 = 0.7346 = 73.46%
e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?
P = 180/(171+163) = 180/334 = 0.5389 = 53.89%
Answer:
a) -3x^3 - 2x + y - 10 = 0
b) it a trinomial
c) not sure. sorry. :(
hope this helps.:)
Answer:
temperature of city a=5
temperature of city b=4
Step-by-step explanation:
Given:
Let temperature of city A= a
temperature of city B=b
As given:
4a=8+3b
a-2b=-3
rearranging 2nd equation we get:
a=-3+2b
substituting above in 1st equation we get:
4(-3+2b)-3b=8
8b - 12 = 3b + 8
8b-3b=12+8
5b = 20
b = 4
Now substituting b=4 in 4a = 8 + 3b
, we get
4a = 8 + 3b
4a = 8 + 3(4)
4a = 8 + 12
4a = 20
a = 20/4
a = 5
temperature of city a and city b on that day is 5C and 4C respectively!
Answer:
(8,0) and (3,0)
Step-by-step explanation: