Segment NO is parallel to the segment KL.
Solution:
Given KLM is a triangle.
MN = NK and MO = OL
It clearly shows that NO is the mid-segment of ΔKLM.
By mid-segment theorem,
<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>
⇒ NO || KL and 
Therefore segment NO is parallel to the segment KL.
Answer:2460
Step-by-step explanation:
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Step-by-step explanation:
3cos2x +sinx=1
3(1-2sin²x)+sinx=1
3-6sin²x+sinx=1
sinx(-6sinx+1)=1
either
sinx=1
sinx=sin(90)
:.x=90
or
-6sinx+1=1
-6sinx=1-1
sinx=0/-6
sinx=sin0,sin180
:.x=0,180and90
If she needs to use 225g of flour for each cake and wants to make 18 cakes she will need 4050g (225x18=4050) of flour but she only has 360g which is obviously not enough flour. For one cake she needs 75g of sugar and since she needs to make 18 cakes she needs 1350g (75x18=1350) of sugar. She only has 135g so it’s not enough.
