4 years ago

-0.04less than or greater than -0.050

Mathematics

1 answer:

katrin [286]4 years ago

6 0

-0.04 less than <span>-0.050</span>

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Answer:

x^4+8x^3+18x-27=0

Step-by-step explanation:

In a equation of the form

$(x-a)^n(x-b)^m=0$

you have roots in x=a and x=b, and multiplicity of n and m respectively.

Hence, the equation is

$(x-(-2))^3(x-1)=0\\(x+2)^3(x-1)=0\\$

by expanding the factors you have

$(x^3+3x^2(3)+3x(3)^2+(3)^3)(x-1)=0\\(x^3+9x^2+27x+27)(x-1)=0\\x^4+9x^3+27x^2+27x-x^3-9x^2-27x-27=0\\x^4+8x^3+18x^2-27=0$

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Step-by-step explanation:

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