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forsale [732]
3 years ago
10

Simplify open parentheses x to the 3 eighths power close parentheses to the 3 fourths power.

Mathematics
2 answers:
seropon [69]3 years ago
5 0
X^9/32...... in other words.... x to the nine over thirty second power
ipn [44]3 years ago
4 0

Answer

(x^\frac{3}{8})^\frac{3}{4}=x^\frac{9}{32}

Step-by-step explanation:

(x^\frac{3}{8})^\frac{3}{4}

To simplify it we need to use exponential property

We multiply the inside exponent with outside exponent

(a^m)^n=a^{mn}

Inside and outside exponents are both fractions. while multiplying fractions we multiply numerator with numerator and denominator with denominator

\frac{3}{8} \cdot \frac{3}{4}=\frac{9}{32}

We cannot simplify the fraction 9/32

(x^\frac{3}{8})^\frac{3}{4}=x^\frac{9}{32}

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Write down the quadratic equation whose roots are $x = -7$ and $x = 1,$ and the coefficient of $x^2$ is 1. Enter your answer in
pav-90 [236]
<h2>Steps:</h2>

So firstly, since we know that the coefficient of x² is 1, this means that this is our base equation:

y = x² + bx + c

Now, since we know that the roots are -7 and 1, set y = 0 and set x = -7 and 1 and simplify:

0=(-7)^2+b(-7)+c\\0=49-7b+c\\-49=-7b+c\\\\0=1^2+b(1)+c\\0=1+b+c\\-1=b+c\\\\-49=-7b+c\\-1=b+c

Now with this, we can set up a system of equations to solve for b and c. For this, I will be using the elimination method. For this, subtract the 2 equations:

\begin{alignedat}{2}-49&=-7b+c\\-(-1&=b+c)\\-48&=-8b\end{alignedat}

Now that the c variable has been eliminated we can solve for b. For this, divide both sides by -8 and your first part of your answer is b = 6.

Now that we know the value of b, plug it into either equation to solve for c:

-49=-7(6)+c\\-49=-42+c\\-7=c\\\\-1=6+c\\-7=c

<h2>Answer:</h2>

<u>Putting it together, your final answer is x² + 6x - 7 = 0.</u>

4 0
3 years ago
Go step by step to reduce the radical of the equation given. (Figure the step for the box)
Rama09 [41]

\sqrt{32} ~~ \begin{cases} 32=2\cdot 2\cdot 2\cdot 2\cdot 2\\ \qquad 2^4\cdot 2\\ \qquad 2^{(2)(2)}\cdot 2\\ \qquad (2^2)^2\cdot 2 \end{cases}\implies \sqrt{(2^2)^2\cdot 2}\implies 2^2\sqrt{2}\implies 4\sqrt{2}

7 0
1 year ago
HELPP PLEASE DUE TOMMOROW PLEASE ANSWER QUESTION B
marin [14]

Answer:

28 non-blue marbles.

Step-by-step explanation:

Initial probability of choosing a blue marble = 4/12

Let the number of non-blue marbles to be added be x.

\frac{4}{12+x} =\frac{1}{10}

12+x=40 (cross multiply)

x=28

4 0
3 years ago
Carl is standing at the top of 35 Ft cliff looking down at a rock for motion in the sea. He estimates the angle of depression is
Liula [17]

The horizontal distance between Carl and the rock at sea is approximately 60.62ft.

Data;

  • Angle = 30 degree
  • Opposite = 35
  • Adjacent = x

<h3>Trigonometric Ratio</h3>

Given the angle of depression from his point to the sea, we can use trigonometric ratio to calculate for the horizontal distance from his location to the bottom of the sea.

SOHCAHTOA

Since we have the value of angle and opposite and we need to calculate the adjacent side of the right-angle triangle, we can use the tangent of the angle to this effect.

Tan\theta = \frac{opposite}{adjacent} \\tan 30 = \frac{35}{x}\\ x = \frac{35}{tan30}\\ x = 60.62ft

The horizontal distance between Carl and the rock at sea is approximately 60.62ft.

Learn more on trigonometric ratio here;

brainly.com/question/12172664

7 0
1 year ago
I NEED THIS ANSWERED PLEASE!!! Can you please write a detailed response. Durning one season, the football team had 15 wins. This
UNO [17]
I’m pretty sure they played 25 games.
3 0
2 years ago
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