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3 years ago

7. A shopkeeper buys 300 identical articles a tota

Mathematics

1 answer:

sashaice [31]3 years ago

3 0

Step-by-step explanation and answers:

300 articles at a total cost of $1500:

$1500 / 300 = $5 / article

Sells 260 articles at a price 20% above this ^ price:

20% of $5 is $1, so $5 + $1 = $6

Then he sells 260 articles at the price of ^ $6

260 * $6 = $1560

Each of the remaining articles is sold at a price that's 50% of the 260 he sold.

He sold those for $6, so he would now sell the last 40 for $3

From the remaining 40 articles, he makes 40 * $3, or $120

The shopkeeper made $1560 + $120 = $1680, which is $180 more than he bought them for ($1500)

Therefore, he made a profit percentage of $180 / $1500, (the amount of profit over the amount spent).

He made a profit percentage, compared to the cost price, of 12%.

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2 years ago

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2 years ago

In a study of 799 randomly selected medical malpractice lawsuits, it was found that 499 of them were dropped or dismissed. Use

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Answer:

Claim is true that most medical malpractice lawsuits are dropped or dismissed.

Step-by-step explanation:

Given :In a study of 799 randomly selected medical malpractice lawsuits, it was found that 499 of them were dropped or dismissed.

To Find : Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed.

Solution:

n = 799

x = 499

We will use one sample proportion test

$\widehat{p}=\frac{x}{n}\\\widehat{p}=\frac{499 }{ 799}\\\widehat{p}=0.6245$

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Formula of test statistic = $\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

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= 7.038

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α =0.05

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2 years ago

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2 years ago

Find the least common multiple of: 12x^3y^2 and 15x^2y^5

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Step-by-step explanation:

Least Common Multiple :The least positive number that is a multiple of two or more numbers.

To find : The least common multiple of: $12x^3y^2$ and $15x^2y^5.$

Since, $12x^3y^2=2\times2\times3\times x^3y^2$

$15x^2y^5=3\times5\times x^2y^5$

The least common multiple of: $12x^3y^2$ and $15x^2y^5.$ = $2\times2\times3\times5\times x^3y^5=60x^3y^5$ [take highest power of x and y ]

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3 years ago