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Marina CMI [18]
2 years ago
12

gn="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
nata0808 [166]2 years ago
8 0
I believe it should be =(1-x) multiple by (y-1)
(1-x) x (y-1)
frutty [35]2 years ago
4 0

Answer:

(x-1) (-y+1)

Step-by-step explanation:

y-xy+x-1

(-yx+y) (x-1)

-y(x-1)  (x-1)

(-y+1) (x-1)

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(p²-pq + q²) ( 3p+ 3q) ​
RUDIKE [14]

Answer:

3p^3 + qp^2 - pq^2 + 3q^3

Step-by-step explanation:

(p²-pq + q²) ( 3p+ 3q)

3p^3 + 3qp^2 - 3qp^2 - 3pq^2 + 3pq^2 + 3q^3

3p^3 + qp^2 - pq^2 + 3q^3

3 0
2 years ago
In 2003 the population of Africa was about 7.7 million people which is 2million more than 3 times the population in 1950
shtirl [24]
The answer to the question is 1.9 million in 1950.
5 0
3 years ago
How many counterexamples do you need to prove a conjecture to be false
Hoochie [10]

Answer:

one , i guess....

because the conjecture is only true if it satisfies all the cases.

3 0
2 years ago
Compound Probability
Sauron [17]

Answer:

9/7is the chance of coming red ball

8 0
2 years ago
Read 2 more answers
Dairy farmers are aware there is often a linear relationship between the age, in years, of a dairy cow and the amount of milk pr
Jobisdone [24]

Answer:

B. A cow of 5 years is predicted to produce 5.5 more gallons per week.

Step-by-step explanation:

Let M(a) = 40.8-1.1\cdot a, where a is the age of the dairy cow, measured in years, and M(a) is the predicted milk production, measured in gallons per week.

Besides, we consider a_{1} and a_{2}, such that a_{1}\ne a_{2}, we define the difference between predicted milk productions (\Delta M) below:

\Delta M = -1.1\cdot (a_{2}-a_{1}) (1)

If we know that a_{1} = 5\,yr and a_{2} = 10\,yr, then the difference between predicted milk productions is:

\Delta M = -1.1\cdot (10-5)

\Delta M = -5.5\,\frac{gal}{week}

That is, a cow of 5 years is predicted to produce 5.5 more gallons per week than a cow of 10 years. Hence, the right answer is B.

6 0
2 years ago
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