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Scorpion4ik [409]
3 years ago
5

a box of candy contains 0.6 of pounds of caramels and 3.6 pounds of coconut what precent of the contents of the box

Mathematics
1 answer:
enyata [817]3 years ago
5 0

Answer:

We know that the box has:

0.6lb of caramels

3.6lb of coconut.

Then the total mass of candy in the box is:

0.6lb + 3.6lb = 4.2lb

This is the 100% of the box.

Now, we can write this as:

4.2lb = 100%

For example, if we want to know which percentage is caramels, we write the equation:

0.6lb = X

We want to find the value of X

Then we have two equations:

0.6lb = X

4.2lb = 100%

Let's take the quotient of these two equations:

(0.6lb/4.2lb) = X/100%

Now we can solve this for X:

(0.6lb/4.2lb)*100% = X = 14.3%

the caramels represent the 14.3% of the wheight of the box.

And for the coconut candy, we have the relation:

3.6lb = Y

Now let's do the same again, we start with the two equations:

3.6lb = Y

4.2lb = 100%

Take the quotient:

(3.6lb/4.2lb) = Y/100%

Solve for Y:

(3.6lb/4.2lb)*100% = Y = 85.7%

Now we found the percentage that represent each type of candy in the box.

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Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

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Step-by-step explanation:

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x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

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also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

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