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MrMuchimi
3 years ago
9

Which of these items will least likely increase pressure in the evaporative emission control system?

Computers and Technology
1 answer:
ella [17]3 years ago
7 0

Answer:

a

Explanation:

a

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Which type of software is offered in trial form or for a limited period of time?
kkurt [141]

The type of software which is offered in trial form or for a limited period of time is called shareware.

Software which are offered for free in trial form or for a limited time period are called shareware. They operate on the principle that once the user understands what the software can offer they will pay to use it later.

Most shareware software has built in countdowns which start as soon as you start the trial and at the end of which access is automatically revoked. They require the user to form a simple account. These versions generally provide a very basic selection of functions and are used to rake in more paying users.

Types of shareware include:

  1. Adware: It stands for advertising-supported software where the advertisements generate revenues.
  2. Demoware: This is a trial version of the original software including all features.
  3. Crippleware: This software is free but provides limited features till it is purchased.
  4. Trialware

This provides the user with full feature access for a time limit and then requires purchase.

You can learn more about shareware software at

brainly.com/question/4593389

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3 0
2 years ago
Select all the correct answers.
Dvinal [7]

Answer: Avoid forwarding a personal email to others and most likely Avoid forwarding jokes and trivia using email.

8 0
3 years ago
Calculate and express your answer in decimal form.
mr Goodwill [35]

Answer:

ポイントが欲しいだけなのかわからない

Explanation:

何語を話していますか

5 0
3 years ago
Suppose you have a stack ADT (i.e., an Abstract Data Type that includes operations to maintain a stack. Design a flowchart or su
Whitepunk [10]

Answer:

One approach would be to move all items from stack1 to stack2 (effectively reversing the items), then pop the top item from stack2 and then put them back.

Assume you use stack1 for enqueueing. So enqueue(x) = stack1.push(x).

Dequeueing would be:

- For all items in stack1: pop them from stack1 and push them in stack 2.

- Pop one item from stack2, which will be your dequeue result

- For all items in stack2: pop them from stack2 and push them in stack 1.

Hope it makes sense. I'm sure you can draw a diagram.

5 0
3 years ago
In what location along a river are you most likely to find a hydropower plant?
saul85 [17]

Answer:

I need help with that too I have that too

Explanation:

3 0
3 years ago
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