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Alchen [17]
2 years ago
9

A model of a famous statue is 1 and one fourth inches tall. The actual statue is 6 and two thirds feet tall. What is the ratio o

f the height of the model to the height of the actual statue in simplest​ form?
Mathematics
1 answer:
Studentka2010 [4]2 years ago
5 0
First, you need to convert 5 1/4 feet to inches. 5.25 x 12 = 63 inches. The ratio of the height of the model to the height of the actual statue in simplest form is 1/42. I don't know if this is correct but I hope this helps you in any way.
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So like, its one of those compare things with: <, >, and = and it says compare: 1/2 of 10 (I know that) but this part stoo
nirvana33 [79]
I’m confused?? Do you just need 1/3 of 12? That’s 4 because 12 x 1 =12 and 12/3 is 4 lol
6 0
2 years ago
What is 110y+10=340 for algebra grade 7
algol [13]
<span> 110y+10=340

Subtract 10 from both sides 

110y=330 

Divide by 110 to get variable on its own 

</span>110y/110=330/110

y=3
7 0
3 years ago
Read 2 more answers
PLEASE HELP: A standard six-sided die is rolled.
amm1812

Answer in fraction form is 1/3

Answer in decimal form is 0.3333

Pick one answer only.

==========================================================

Explanation:

The sample space is the set of all possible outcomes. In this case, the outcomes consist of values between 1 and 6

S = sample space

S = {1,2,3,4,5,6}

There are 6 items here. Let B = 6.

We want to roll a number greater than 4, so the event space we're after is

E = {5,6}

which consists of 2 items. Let A = 2.

The probability we want is A/B = 2/6 = 1/3 = 0.3333

So if you go with the fraction option, then you'll type in 1/3

If you go with the decimal option, then you'll type in 0.3333

4 0
2 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
1 year ago
There is a spinner with 12 equal areas, numbered 1 through 12. If the spinner is spun
Tomtit [17]

Answer:

1/12

Step-by-step explanation:

There is only number between 1 and 12 that is both a multiple of 5 and 2, that being 10. 10 has an equal chance out of all the other numbers that can be spun, and there are 12 numbers, so 10 has a 1/12 chance of being spun.

6 0
2 years ago
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