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4 years ago

Mr. I.C green wanted to plant a brand new yard. His yard was 17 yards by 8 yards. What was the area of his yard?

Mathematics

1 answer:

Free_Kalibri [48]4 years ago

5 0

Answer:

17 x 8= 136 ft

Step-by-step explanation:

You might be interested in

4(-7)<br>show work please

Lostsunrise [7]

The equation is asking you to multiply.

= 4 * -7

= -28

Hope This Helped! Good Luck!

6 0

4 years ago

Read 2 more answers

56.27 in expanded form

Lana71 [14]

Answer:

Step-by-step explanation:

56.27 =

+ 6

+ 0.2

+ 0.07

Expanded Factors Form:

56.27 =

5 × 10

+ 6 × 1

+ 2 × 0.1

+ 7 × 0.01

Expanded Exponential Form:

56.27 =

5 × 101

+ 6 × 100

+ 2 × 10-1

+ 7 × 10-2

Word Form:

56.27 =

fifty-six and twenty-seven hundredths

5 0

3 years ago

Please help 49÷k –3=46

Andreas93 [3]

$\frac{49}{k} -3 = 46$
$\frac{49}{k} = 49$ . . . . add 3
$\frac{49}{49} = k$ . . . . multiply by $\frac{k}{49}$

k = 1

4 0

3 years ago

The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?

svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

$V(t) = V(0)(1-r)^{t}$

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that $r = 0.16$

$V(t) = V(0)(1-r)^{t}$

$V(t) = V(0)(1-0.16)^{t}$

$V(t) = V(0)(0.84)^{t}$

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

$V(t) = V(0)(0.84)^{t}$

$0.5V(0) = V(0)(0.84)^{t}$

$(0.84)^{t} = 0.5$

$\log{(0.84)^{t}} = \log{0.5}$

$t\log{0.84} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.84}}$

$t = 3.98$

The half life of the car is 3.98 years.

7 0

4 years ago

Write the value of the underlined digit 7,270

RSB [31]

I am sorry but I do not see the underlined digit, but I will put it this way. 7 in the thousands place is worth 7000, 2 in the hundreds place is worth 200, 7 in the tens place is worth 70, and 0 in the ones place is worth 0.

Hope this helped!

Nate

3 0

4 years ago