The acceleration of the block is
Explanation:
The expression for the force of friction acting on the block is (assuming the surface is horizontal and flat):
where
is the coefficient of friction
m is the mass of the block
g is the acceleration of gravity
and where the negative sign means the direction of the force is opposite to that of the motion of the block
If this is the only force acting on the object, then this is also the resultant force, so we can rewrite Newton's second law as:
where
a is the acceleration of the block
Re-arranging the equation,
And so this is the expression for the acceleration of the block acted upon the force of friction.
In this problem, we have:
Solving,
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Answer:
μs = 0.75
μk = 0.58
Explanation:
From a force diagram:
(1)
(2)
When it starts slipping, friction force is the maximum and acceleration is 0. Replacing these conditions on (1):
Solving for μs:
μs = tan 36.7° = 0.75
When it moves at constant speed, friction force is kinetic friction and acceleration is 0. With these conditions the coefficient is:
μk = tan 30.1° = 0.58
Answer:
=(5.7 x
i - 2.24 x
j) kgm/s
Explanation:
Due to earths gravity, force on asteroid is given by:
r^
Plugging in the values, we have
F= [(6.67x)(1500)(5.97 x
)(8x
i + 9x
j)] / ((8x
)² + (9x
)²
F= 2736 i^ + 3078 j^
In order find the final momentum of the Asteroid, apply impulse momentum theorem
=
+ FΔt
= 1500(3.5 x
i - 1.8x
j) + (2736i + 3078j)(1.5x
)
=(5.7 x
i- 2.24 x
j)kgm/s
Answer:
Acceleration of proton will be
Explanation:
We have given surface charge density of an infinite charged plate
Electric field due to infinite sheet charge is given by
Charge in proton is given by
So force on proton
Mass of proton
According to newtons second law force F = mass × acceleration
So