Answer:
c) True. factor four
Explanation:
The energy density of an electromagnetic wave is given by
u = ½ ε₀ E² = B² / 2μ₀
Where ε₀ is the dielectric constant and μ₀ the magnetic permittivity.
Let's apply this equation to the present case
If we double the electro field
E ’= 2 E₀
u’= ½ ε₀ (2E₀)²
u’= ½ ε₀ Eo² 4
u’= 4 u₀
Therefore the energy is multiplied by four
Let's check the answers
a) False
b) False
c) True
d) False
e) False
Reaction time will stay the same for each person however the faster the car is going the faster someones reaction time would need to be react to something that happened. therefore it might seem like someone had a slower reaction time when a car is moving faster because everything happens faster when you are moving faster
I hope I've helped!
The internal energy of the gas after the adiabatic compression will be 30.398 × 10⁶ J
<h3>What is work done by gas?</h3>
When energy is moved from one store to another, work is completed. Work done on the gas is taken as -ve.
Given data;
pressure(P)=3.0 atm = 303975 N/m²
The initial volume, V₁
work is done on the gas., W=?(-ve)
Change in heat, ΔQ=0
Change in the internal energy of the gas., ΔE
The work done on the gas;
W = -PΔV
W= - 303975 N/m² × 100 cm³
W = - 30.3 × 10⁶ J
The internal energy is found as;
ΔE=q+w
ΔE= 0-30.3 × 10⁶ J
ΔE= -30.3 × 10⁶ J
E₂-E₁= -30.3 × 10⁶ J
E₂ = -30.3 × 10⁶ J +500
E₂ = 30.398 × 10⁶ J
Hence, the internal energy of the gas after the adiabatic compression will be 30.398 × 10⁶ J
To learn more about the work done by gas refer to;
brainly.com/question/12539457
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Answer:
Correct option a. one state variable T.
Explanation:
In the case of an ideal gas it is shown that internal energy depends exclusively on temperature, since in an ideal gas any interaction between the molecules or atoms that constitute it is neglected, so that internal energy is only kinetic energy, which depends Only of the temperature. This fact is known as Joule's law.
The internal energy variation of an ideal gas (monoatomic or diatomic) between two states A and B is calculated by the expression:
ΔUAB = n × Cv × (TB - TA)
Where n is the number of moles and Cv the molar heat capacity at constant volume. Temperatures must be expressed in Kelvin.
An ideal gas will suffer the same variation in internal energy (ΔUAB) as long as its initial temperature is TA and its final temperature TB, according to Joule's Law, whatever the type of process performed.
The weight that will be lifted will be distributed into the two cylinders. First, we must calculate the force that one cylinder is able to bear, which is calculated using:
Pressure = Force / Area
Force = Pressure * Area
Force = 2000 * π * (3/2)²
Force = 14,137.2 Lbs
Combined weight bearable by the two cylinders:
2 * 14,137.2
= 28,000 lbs
