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3 years ago

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The relative density ofbrass is 8.4. Which of

1 answer:

drek231 [11]3 years ago

8 0

A.brass is heavier than water.

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A flat loop of wire consisting of a single turn of cross-sectional area 8.20 cm2 is perpendicular to a magnetic field that incre

olga nikolaevna [1]

Answer:

The induced current is $I = 6.25*10^{-4} \ A$

Explanation:

From the question we are told that

The number of turns is $N = 1$

The cross-sectional area is $A = 8.20 cm^2 = 8.20 * 10^{-4} \ m^2$

The initial magnetic field is $B_i = 0.500 \ T$

The magnetic field at time = 1.02 s is $B_t = 2.60 \ T$

The resistance is $R = 2.70\ \Omega$

The induced emf is mathematically represented as

$\epsilon = - N * \frac{ d\phi }{dt}$

The negative sign tells us that the induced emf is moving opposite to the change in magnetic flux

Here $d\phi$ is the change in magnetic flux which is mathematically represented as

$d \phi = dB * A$

Where dB is the change in magnetic field which is mathematically represented as

$dB = B_t - B_i$

substituting values

$dB = 2.60 - 0.500$

$dB = 2.1 \ T$

Thus

$d \phi = 2.1 * 8.20 *10^{-4}$

$d \phi = 1.722*10^{-3} \ weber$

So

$|\epsilon| = 1 * \frac{ 1.722*10^{-3}}{1.02}$

$|\epsilon| = 1.69 *10^{-3} \ V$

The induced current i mathematically represented as

$I = \frac{\epsilon}{ R }$

substituting values

$I = \frac{1.69*10^{-3}}{ 2.70 }$

$I = 6.25*10^{-4} \ A$

7 0

4 years ago

What kind of acceleration occurs when an object speeds up?

Fantom [35]

Answer:

Postive Acceleration

Explanation:

3 0

3 years ago

Read 2 more answers

If 5 mm of rain falls in a 100 m2 field, what volume of rain, in m3, fell in the field?

Nina [5.8K]

The volume of rain that fells in the field is simply given by the area of the field, which is

$A=100 mm^2$

multiplied by the height of rain that fell, which is

$h=5.0 mm$

Therefore, the volume is

$V=hA=(5 mm)(100 mm^2)=500 mm^3$

7 0

4 years ago

A driver brings a car to a full stop in 2.0 s. If the car was initially

vagabundo [1.1K]

Answer:

$\boxed {\boxed {\sf D. \ -11 \ m/s^2}}$

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

$a=\frac{v_f-v_i}{t}$

where Vf is the final velocity, Vi is the initial velocity, and t is the time.

Since the car came to a complete stop, it's final velocity was 0 meters per second.

The initial velocity was 22 meters per second.

The time was 2.0 seconds.

$v_f=0 \ m/s\\v_i=22 \ m/s\\t= 2.0 \ s$

Substitute the values into the formula.

$a=\frac{0 \ m/s-22 \ m/s}{ 2.0 \s }$

Subtract in the numerator first.

0 m/s- 22 m/s = -22 m/s

$a=\frac{-22 \ m/s}{2.0 \ s}$

Divide.

$a= -11 \ m/s^2$

The acceleration of the car was -11 meters per square second. The negative acceleration indicates slowing down/stopping.

8 0

3 years ago

Which item could you use in place of an ammeter to demonstrate that a

love history [14]

Answer:

the answer is D

Explanation:

6 0

3 years ago