Let A represents the event that DVD has a video effect.
So,
P(A) = 1.5 %
Let B represents the event that DVD has a audio defect.
So,
P(B) = 0.8 %
A ∩ B represents that DVD has both audio and video defect.
So,
P(A∩B) = 0.4%
Part a)
A ∪ B represents that DVD has a video or audio defect.
P(A∪B) = P(A)+P(B)-P(A∩B) = 1.5 + 0.8 - 0.4 = 1.9%
Thus the probability that the DVD purchased by the customer has a video or audio defect is 1.9%.
Part b)
The complement of P(A∩B) will represent the probability that the DVD does not have video or audio defect.
So, the probability that DVD purchased by customer does not have video or audio defect is 1 - 0.4 = 0.96%
Leah ran 6 miles in total on Monday and Tuesday.
Here you go :) pls give brainliest
Answer:
-The answer is 
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Step-by-step explanation:
When you divide numbers/variables with exponents, the exponents will subtract each other:
