PLEASE HELP!!! I NEED THE ANSWER SOON :)

If $6,000 is placed in an account with an annual interest rate of 6%, how long will it take the amount to triple if the interest

Dennis_Churaev [7]

3p=p(1+0.06)^t
3=(1.06)^t
T=log(3)÷log(1.06)
T=18.9 years

4 0

3 years ago

Jonah runs a bakery, and his most popular item is cinnamon raisin bread. He has two options to purchase raisins.

MAXImum [283]

Answer:

He needs to purchase more raisins then because since its the most popular item he will get more money and customores.

Step-by-step explanation:

6 0

3 years ago

A manufacturer of a new medication on the market for Alzheimer's disease makes a claim that the medication is effective in 65% o

NeX [460]

Answer:

$z=\frac{0.639 -0.65}{\sqrt{\frac{0.65(1-0.65)}{180}}}=-0.309$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults with the medication was effective is not significantly less than 0.65

Step-by-step explanation:

Data given and notation

n=180 represent the random sample taken

X=115 represent the adults with the medication was effective

$\hat p=\frac{115}{180}=0.639$ estimated proportion of adults with the medication was effective

$p_o=0.65$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is less than 0.65.:

Null hypothesis: $p \geq 0.65$

Alternative hypothesis: $p < 0.65$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.639 -0.65}{\sqrt{\frac{0.65(1-0.65)}{180}}}=-0.309$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults with the medication was effective is not significantly less than 0.65

3 0

3 years ago

Marvin used the Quantitative Reasoning Process to build a budget while he is going to college. He worked hard over the summer an

Llana [10]

For Marvin used the Quantitative Reasoning Process to build a budget while he is going to college. He worked hard over the summer and saved $2,595.9 to live on during the next two semesters of school. Marvin will receive a scholarship each semester for $958.35 money can Marvin spend each month, on average, for things like groceries, entertainment, and miscellaneous items is mathematically given as

$4512.6

<h3>How much money can Marvin spend each month, on average, for things like groceries, entertainment, and miscellaneous items?</h3>

Savings with Marvin = $2,595.9

Scholarship amount = $958.35

Total Scholarship amount received in 2 semesters = $958.35 X 2 = $ 1916.7

Now total money that Paolo have = (Savings with Marvin) + (Total Scholarship amount received in both semesters) = $2,595.9 + $1916.7 = $ 4512.6

Tuition & books cost = $2000

Tuition & books cost for 2 semesters = $2000 X 2 = $4000

Housing cost for 2 semester contract =$1,000

Total expenses in books and housing = $4000+ $1000 = $5000

Money left with Marvin after Total expenses in books and housing = $ 4512.6 - $5000 = −487.4

This means he has overspent.

as no. of months in 2 semesters = 8

Amount that Marvin would be in debt each month = −487.4/8 = −$60.925