Ask question

Ask question

All categories

3 years ago

8

PLEASE HELP!!! I NEED THE ANSWER SOON :)

1 answer:

densk [106]3 years ago

4 0

$y=2x \newline y= x^{2} -3$

Substitue 2x for y in the second equation:

$2x= x^{2} -3$

Rearrange to $a x^{2} +bx+c=0$ form:

$x^{2} -2x-3=0$

Factor:

$(x-3)(x+1)=0$

Zeros are $x=3$ and $x=-1$

To find y-coordinates of pts of intersection, plug these x-values into first equation to get $y=-2$ and $y=6$

You might be interested in

Let f(x)=4-x^2, g(x) =2-x find (f+g)(x) and its domain

boyakko [2]

Add like terms together..
-x^2 -x+6
............

8 0

3 years ago

I WILL GIVE YOU BRAINLY PLSS

Mekhanik [1.2K]

Answer:

B

Step-by-step explanation:

you can't have 143

but you also have toe have less

so < 143

5 0

2 years ago

Read 2 more answers

Determine value of y

Alik [6]

Cos 28 = 18/ y
so
y = 18 / cos 28
y = 18 /.8829
y = 20.4

8 0

3 years ago

Question 3 "Try Again." Mary needs 3 feet of boondoggle for a craft project.

kati45 [8]

Answer:

$9.00

Step-by-step explanation:

We can use conversion factors to solve this equation. The multiplication sequence that I got is shown below:

$\frac{3ft}{1}$ × $\frac{12 in}{1ft}$ × $\frac{0.25}{1in}$

Our feet and inches cancel out and we get the final expression $\frac{3*12*0.25}{1}$ , which is equal to 9, or $9.00.

Hopefully that was helpful! :)

7 0

2 years ago

Which function has an inverse function?

daser333 [38]

Answer: Option B

Step-by-step explanation:

By definition, only those functions that are one to one have an inverse function.

A function is one by one if there are not two different input values, $x_1$ and $x_2$ , that have the same output value y

Note that the function $f(x)= \frac{|x+3|}{5}$ is not a one-to-one function

When x=2 $f(x)= \frac{|2+3|}{5}=1\ ,\ \ y=1$

When x=8 $f(x)= \frac{|-8+3|}{5}=1\ \ ,\ y=1$

Note that the function $f(x)= \frac{x^4}{7}+ 27$ is not a one-to-one function

When x=1 $f(x)= \frac{(1)^4}{7}+27\ ,\ \ y=\frac{190}{7}$

When x=-1 $f(x)= \frac{(-1)^4}{7}+27\ ,\ \ y=\frac{190}{7}$

Note that the function $f(x)= \frac{1}{x^2}$ is not a one-to-one function

When x=1 $f(x)= \frac{1}{(1)^2}\ ,\ \ y=1$

When x=-1 $f(x)= \frac{1}{(-1)^2}\ ,\ \ y=1$

Then the answer is the option B.

You can verify that The function $f (x) = x ^ 5-3$ is a one-to-one function and therefore its inverse is a function

5 0

2 years ago