Question

PLEASE HELP!!! I NEED THE ANSWER SOON :)

Answer 1

$y=2x \newline y= x^{2} -3$

Substitue 2x for y in the second equation:

$2x= x^{2} -3$

Rearrange to $a x^{2} +bx+c=0$ form:

$x^{2} -2x-3=0$

Factor:

$(x-3)(x+1)=0$

Zeros are $x=3$ and $x=-1$

To find y-coordinates of pts of intersection, plug these x-values into first equation to get $y=-2$ and $y=6$