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sweet-ann [11.9K]
3 years ago
10

In the periodic table notation below what information does the number 40.08 tell you

Physics
1 answer:
tia_tia [17]3 years ago
5 0

Answer:

The number above the symbol is the atomic mass (or atomic weight). This is the total number of protons and neutrons in an atom. The number below the symbol is the atomic number and this reflects the number of protons in the nucleus of each element's atom. Every element has a unique atomic number.

Explanation:

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A man with a mass of 60 kg rides a bike with a mass of 13 kg. What is the force needed by the man to accelerate the bike at 0.90
Tanzania [10]
Bro it would be9999999 cuh cuh
8 0
3 years ago
A 41.0 kg child is riding a playground merry-go-round that is rotating at 60.0 rev/min. What centripetal force (in N) is exerted
Tatiana [17]

Answer:505.94 N

Explanation:

Given

mass of child (m)=41 kg

N=60 rpm

\omega =\frac{2\pi N}{60}=4\pi rad/s

Radius(r)=1.25 m

and centripetal acceleration is given by m\omega ^2r

F_c=41\times (4\pi )^2\times 1.25=505.94 N

3 0
4 years ago
Plasma easily conducts electricity and responds to magnetic fields, but why?
Valentin [98]

Explanation:

Plasma can conduct electricity because plasma consists of electrically charged particles called ions, instead of uncharged particles such as atoms or molecules.

6 0
4 years ago
If Rebecca is traveling at 7 m/s east for 1 hour how much is Rebecca displaced
Mekhanik [1.2K]

Answer:

25.2 km east

Explanation:

The relationship between velocity and displacement is given by:

v=\frac{d}{t}

where

v is the velocity

d is the displacement

t is the time

In this problem, we have:

v=7 m/s east is Rebecca's velocity

t=1 h=60 min=3600 s is the time taken

Re-arranging the equation, we can find Rebecca's displacement:

d=vt=(7 m/s)(3600 s)=25,200 m=25.2 km

and the direction is same as velocity (east)

3 0
3 years ago
The inclined plane in the figure above has two sections of equal length and different roughness. The dashed line shows where sec
saveliy_v [14]

The static friction exerted on the block by the incline is \mu _ s _1 Mgcos \ \theta.

The given parameters;

  • <em>mass of the block, = M</em>
  • <em>coefficient of static friction in section 1, = </em>\mu_s_1<em />
  • <em>angle of inclination of the plane, = θ</em>

<em />

The normal force on the block is calculated as follows;

Fₙ = Mgcosθ

The static friction exerted on the block by the incline is calculated as follows;

F_s = \mu_s F_n\\\\F_s = \mu _s_1(Mg cos\ \theta)\\\\F_s = \mu _s_1 Mgcos\ \theta

Thus, the static friction exerted on the block by the incline is \mu _ s _1 Mgcos \ \theta

Learn more here:brainly.com/question/17237604

3 0
3 years ago
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