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Darya [45]
3 years ago
6

Please answer with an explanation.

Physics
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

A, D, E

Explanation:

The force of Earth's gravitational pull is equal to the mass of the object times the acceleration due to gravity:

W = mg

The greater the mass, the greater the pull.  A truck, bicycle, and camel all have greater mass than a baseball.

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An enclosure has an inside area of 50 m2, and its inside surface is black and is maintained at a constant temperature. A small o
tatuchka [14]

Answer:

Explanation:

The enclosure will behave as black body . For black body , the formula for radiant energy is given by Stefan's law as follows

E = σ A T⁴ where σ = 5.67 x 10⁻⁸ W m⁻² T⁻⁴

Area A = .01 m²

E = 48 W

48 = .01 x 5.67 x 10⁻⁸ T⁴

T⁴ =  846.56 x 10⁸

T= 539 K

7 0
3 years ago
Poate cineva sa imi rezolve fisa Asta pana Maine?
Firlakuza [10]

Answer:

httfytstuytshysts

Explanation:htrhstrhhstrsstrthrssr

5 0
3 years ago
A 13.5 μF capacitor is connected to a power supply that keeps a constant potential difference of 22.0 V across the plates. A pie
-BARSIC- [3]

a) 3.27\cdot 10^{-3} J

b) 11.60\cdot 10^{-3} J

c) 8.33\cdot 10^{-3} J

Explanation:

a)

The energy stored in a capacitor is given by

U=\frac{1}{2}CV^2

where

C is the capacitance of the capacitor

V is the potential difference across the plates of the capacitor

For the capacitor in this problem, before insering the dielectric, we have:

C=13.5 \mu F = 13.5\cdot 10^{-6}F is its capacitance

V = 22.0 V is the potential difference across it

Therefore, the initial energy stored in the capacitor is:

U=\frac{1}{2}(13.5\cdot 10^{-6})(22.0)^2=3.27\cdot 10^{-3} J

b)

After the dielectric is inserted into the plates, the capacitance of the capacitor changes according to:

C'=kC

where

k = 3.55 is the dielectric constant of the material

C is the initial capacitance of the capacitor

Therefore, the energy stored now in the capacitor is:

U'=\frac{1}{2}C'V^2=\frac{1}{2}kCV^2

where:

C=13.5\cdot 10^{-6}F is the initial capacitance

V = 22.0 V is the potential difference across the plate

Substituting, we find:

U'=\frac{1}{2}(3.55)(13.5\cdot 10^{-6})(22.0)^2=11.60\cdot 10^{-3} J

C)

The initial energy stored in the capacitor, before the dielectric is inserted, is

U=3.27\cdot 10^{-3} J

The final energy stored in the capacitor, after the dielectric is inserted, is

U'=11.60\cdot 10^{-3} J

Therefore, the change in energy of the capacitor during the insertion is:

\Delta U=11.60\cdot 10^{-3}-3.27\cdot 10^{-3}=8.33\cdot 10^{-3} J

So, the energy of the capacitor has increased by 8.33\cdot 10^{-3} J

8 0
3 years ago
*Urgent* I WILL GIVE BRAINLIEST
Butoxors [25]

Answer:

walking to school

Explanation:

Driving a car to school

, and taking the bus to school​ both take up energy, unlike walking to school.

unless ur talking about energy, counting energy you produce and use to complete things, then it would be the 3rd one, taking the bus to school.

4 0
3 years ago
True or false according to newtons 1st law an unbalanced force can change the motion of an object
lisov135 [29]
I think this is true
6 0
3 years ago
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