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ruslelena [56]
2 years ago
15

The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s isJ. (Formula: )

Physics
2 answers:
tekilochka [14]2 years ago
8 0
25 Joule
Formula=.5*mass*velocity^2
madreJ [45]2 years ago
4 0

Answer:

25 J

Explanation:

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its velocity

For the ball in the problem, we have:

mass: m = 0.5 kg

v = 10 m/s

Substituting into the formula, we find

K=\frac{1}{2}(0.5 kg)(10 m/s)^2=25 J

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The rate of acceleration of the crate would be 1 m/s^2 because the equation for force is F=ma and when you plug in your numbers you get 10=10a so a=1
8 0
3 years ago
If an object is placed at the center of carvature of a convance mirror the image formed is called
Natasha_Volkova [10]

Answer:

When the object is placed between centre of curvature and principal focus of a concave mirror the image formed is beyond C as shown in the figure and it is real, inverted and magnified.

3 0
2 years ago
The muzzle velocity of a rifle bullet is 709 m s−1along the direction of motion. If the bullet weighs 35 g, and the uncertainty
nydimaria [60]

Answer:

Uncertainty in position of the bullet is \Delta x=1.07\times 10^{-33}\ m

Explanation:

It is given that,

Mass of the bullet, m = 35 g = 0.035 kg

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The uncertainty in momentum is 0.20%. The momentum of the bullet is given by :

p=mv

p=0.035\times 709=24.81\ kg-m/s

Uncertainty in momentum is,

\Delta p=0.2\%\ of\ 24.81

\Delta p=0.049

We need to find the uncertainty in position. It can be calculated using Heisenberg uncertainty principal as :

\Delta p.\Delta x\geq \dfrac{h}{4\pi}

\Delta x=\dfrac{h}{4\pi \Delta p}

\Delta x=\dfrac{6.62\times 10^{-34}}{4\pi \times 0.049}

\Delta x=1.07\times 10^{-33}\ m

Hence, this is the required solution.

7 0
3 years ago
A disk-shaped platform has a known rotational inertia ID. The platform is mounted on a fixed axle and rotates in a horizontal pl
Zarrin [17]

Answer:

Explanation:

The angular momentum of that same disk-sphere remains unchanged the very same way before and after the impact of the collision when the clay sphere adheres to the disk.

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Recall that:

The Kinetic energy is given by:

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where;

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As a result, just after the collision, the system's total kinetic energy decreases.

5 0
2 years ago
Can someone please help me it's urgent!
Alik [6]

Answer:

It's the first one

Explanation for answer:

7 0
3 years ago
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