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Aleonysh [2.5K]
3 years ago
11

A number has the digit 2,5,and4. To the nearest 100, the number rounds to 200. What is the number?

Mathematics
2 answers:
Masteriza [31]3 years ago
6 0
254 is your answer because you don't want to put the 5 at the end because the you round to 260
marusya05 [52]3 years ago
3 0
To start off we need to recognize that the number rounds to 200.  This means that we need to choose the closest thing to 200, which would be the 2.

Now we know that the 2 goes in the hundreds place, there is only 2 digits left, 5, and 4.  Now you can't put a 5 in the tens place because then it would round it up to 300 ( Anything greater than or equal to 5  gets rounded up)  So that means that the 4 has to go in the tens place and the 5 in the ones place.

The final number ends up being:

245
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30÷10 divide until you find the ten thousand digit
klemol [59]

Answer:

The ten thousandth digit would be 0.

Step-by-step explanation:

30/10=3

3 is a whole number so there would be no decimal which means that in the ten thousandth place would be 0

30/10=3.0000

4 0
3 years ago
Find the intervals on which the function is increasing or decreasing.
Assoli18 [71]
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.

f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:

Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
6 0
3 years ago
Subtract 5b − 3c from −8a − 2b − 10c
erik [133]

Answer:

-8a - 7b - 7c

Step-by-step explanation:

-8a - 2b - 10c - (5b - 3c)

Negate 5b and -3c

-8a - 2b - 10c - 5b + 3c = -8a - 7b - 7c

3 0
3 years ago
Read 2 more answers
Which statement best reflects the solution(s) of the equation?
Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1} and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0

Now, factoring the term:

x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}  the denominator becomes zero i.e

\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2  in the equation,

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}

\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/2456302

#learnwithBrainly

5 0
4 years ago
Help again idk how to do this
creativ13 [48]

Answer:

it's,

( {5}^{3} ) ^{ - 4}  \\

Step-by-step explanation:

( {5}^{3} ) ^{ - 4}  \\  =  {5}^{ - 12}

5 0
3 years ago
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