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Nataly_w [17]
2 years ago
15

PLEASE HELP ASAP 30 POINTS!! Show all work!

Mathematics
2 answers:
Lisa [10]2 years ago
7 0

Answer:

P- 6500

R-1.4%

T- 3yrs

I-?

I first find simple interest,

I=P×R×T÷100

=273

then you add your answer to the price(6500)

273+6500=6773

Mazyrski [523]2 years ago
3 0

Answer:

D, 6500 increased by 1.4% is 6591 plus another 1.4% which is 6683 and for the last year you add another 1.4% to get the final answer which is D 6,776.84

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a survey of students at a university shows that 3 out of 5 drink coffee. of the students who drink coffee, 1 out of 8 adds cream
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Answer:

900 students

Step-by-step explanation:

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1/8 x 7,200 = 900 who drink coffee with cream

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A poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ag
Katyanochek1 [597]

Answer:

At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

Step-by-step explanation:

Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.

Let five years ago be group I X and as of now be group II Y

H_0: p_x =p_y\\H_a: p_x \neq p_y

(Two tailed test at 5% level of significance)

                Group I            Group II              combined p

n                  270                 300                         570

favor            120                  140                          260

p                   0.4444            0.4667                   0.4561

Std error   for differene = \sqrt{\frac{0.4561(1-0.4561)}{570} } \\=0.0209

p difference = -0.0223    

Z statistic = p diff/std error =       -1.066

p value =0.2864

Since p value >0.05, we accept null hypothesis.

        At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

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