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3 years ago

Marissa works in a bread shop every hour

Mathematics

1 answer:

anzhelika [568]3 years ago

4 0

Answer:

She's getting paid minimum wage, in debt, and struggling in college.

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Help i need Help im struggling

HACTEHA [7]

Answer:

c.2,400 I think is c. nose you

Step-by-step explanation:

╮(╯_╰)╭

8 0

3 years ago

How do I solve 4[2.5 + 3 (20 + 7)] ?

DerKrebs [107]

$4[2.5+3(20+7)]=4[2.5+3 \cdot 27]=4[2.5+81]=4 \cdot 83.5=334$

3 0

3 years ago

Read 2 more answers

How many equivalence relations are there on the set 1, 2, 3]?

Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0

4 years ago

A cyclist travels 20 miles in the same amount of time it takes a hiker to walk 6 miles. The rate of the cyclist is 7 mph faster

Anna11 [10]

Answer:

The speed of the cyclist is 10 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by cyclist = $D_1$ = 20 miles

The distance cover by biker = $D_2$ = 6 miles

The speed of biker = $S_2$ = s mph

The speed of cyclist = $S_1$ = 7 + s mph

The time taken by both cyclist and biker = t hour

Now. Distance = Speed × Time

So, $D_1$ = $S_1$ × t

Or, 20 = s × t

Or, t = $\frac{20}{7+s}$ .....1

And ,

$D_2$ = $S_2$ × t

or, 6 = s t

Or, t = $\frac{6}{s}$ ....2

From Eq 1 and 2

I.e $\frac{20}{7+s}$ = $\frac{6}{s}$

Or, 20 s = 6 ( 7 + s )

Or, 20 s - 6 s = 42

Or, 14 s = 42

∴ s = $\frac{42}{14}$

I,e s = 3 miles per hour

So, The speed of biker = $S_2$ = s = 3 miles per hour

And The speed of cyclist = $S_1$ = 7 + s = 7 + 3= 10 miles per hour

Hence The speed of the cyclist is 10 miles per hour . Answer

4 0

3 years ago

Right triangle ABC is on a coordinate plane. Segment AB is on the line y = 2 and is 3 units long.Point C is on the line x = -1.

nexus9112 [7]

Answer:

Step-by-step explanation:

Area = 1/2( base times height)

since the height is perpendicular to the base

therefore

6 = 1/2(3) h

12 =3h

4=h

4 units away from the y=2 line is at the y coordinate of 6

7 0

3 years ago