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Mathematics

2 answers:

Tasya [4]4 years ago

6 0

Answer:

- 2/3

Step-by-step explanation:

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Tanzania [10]4 years ago

6 0

Answer:

-2/3

Step-by-step explanation:

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Let a = 0.9876 and b = 0.9887 with N = 2, calculate the midpoint.

rodikova [14]

Answer:

For a=0.9876 and b=0.9887 mid point will be 0.98815

Step-by-step explanation:

We have given a = 0.9876 and b = 0.9887

And N = 2

We have to find the mid point

For finding mid point we know that formula

Midpoint $=\frac{a+b}{2}$ , here we have given a=0.9876 and b = 0.9887

So midpoint will be $=\frac{0.9876+0.9887}{2}=\frac{1.9763}{2}=0.98815$

So for a=0.9876 and b=0.9887 mid point will be 0.98815

5 0

3 years ago

Ask your teacher find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using i

liberstina [14]

Answer:

ln(5/3)

Step-by-step explanation:

The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.

<h3>Limit</h3>

We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.

$\diplaystyle \lim\limits_{x\to1}{(\ln(x^5-1)-\ln(x^3-1))}=\lim\limits_{x\to1}\ln{\left(\dfrac{x^5-1}{x^3-1}\right)}\\\\=\lim\limits_{x\to1}\ln\left(\dfrac{x^4+x^3+x^2+x+1}{x^2+x+1}\right)=\ln{\dfrac{5}{3}}$