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dimaraw [331]
3 years ago
9

A person places $8890 in an investment account earning an annual rate of 7.7% compounded continuously using the formula v=pert w

here v is the value of the account in t years p is the principal initially invested e is the base of a natural logarithm and r is the rate of interest determine the amount of money to be nearest cent in the account after 3 years
Mathematics
1 answer:
34kurt3 years ago
5 0

Answer:

11200.15

Step-by-step explanation:

P=8890

t=3

V=Pe^rt

V=8890e^0.077(3)

V=8890e^0.231

V=11200.15

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A bag contains 3 red marbles and 4 blue marbles.
vazorg [7]

The probability of getting two marbles of the same colour is 25/49.

<h3>What is defined as the probability?</h3>
  • Probability is simply the likelihood of something occurring. When we are uncertain about the outcome of an event, we can discuss the probabilities of various outcomes—how likely they are.
  • Statistics is the study of events governed by probability.

The formula for finding the probability is;

Probability(event) = favourable outcome/total outcome

Total red marbles in the bag = 3.

Total blue marbles in the bag = 4.

Total marbles = 7.

As, the case is with replacement total marble will remain same after the drawn of first marble.

The probability that first marble be red = 3/7

The probability that first marble be red = 3/7

The combine probability getting red marble = 3/7 × 3/7 = 9/49

The probability that first marble be blue = 4/7

The probability that first marble be blue = 4/7

The combine probability getting blue marble = 4/7 × 4/7 = 16/49.

The condition for OR either red or blue marble be drawn.

Thus,

The combine probability getting marble of same colour = 9/49 + 16/49.

Therefore, the combine probability getting marble of same colour = 25/49.

To know more about the probability, here

brainly.com/question/24756209

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2 years ago
Expand and simplify 5(2a – c) + 4(3a + 2c)
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M(Pb(C2H5)4 = 207.2 + 4(28.0 + 5)
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Hope this helps !

Photon

4 0
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First, I would find the total area that Lisa needs to paint.
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