Answer:
B
Step-by-step explanation:
These lines dont cross CD and are not parrellel which is what skew lines are.
Answer:
The equation of the line would be y + 4 = -1/8(x + 6)
Step-by-step explanation:
To find the point-slope form of the line, start by finding the slope. You can do this using the slope formula below along with the two points.
m(slope) = (y2 - y1)/(x2 - x1)
m = (-4 - -5)/(-6 - 2)
m = 1/-8
m = -1/8
Now that we have the slope, we can use that along with one of the points in the base form of point-slope.
y - y1 = m(x - x1)
y + 4 = -1/8(x + 6)
1. Let a and b be coefficients such that
Combining the fractions on the right gives
so that
2. a. The given ODE is separable as
Using the result of part (1), integrating both sides gives
Given that y = 1 when x = 1, we find
so the particular solution to the ODE is
We can solve this explicitly for y :
![\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|](https://tex.z-dn.net/?f=%5Cln%7Cy%7C%20%3D%20%5Cln%5Cleft%7C%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%5Cright%7C)
![\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%7D)
2. b. When x = 9, we get
![y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B45%7D%7B21%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B15%7D7%7D%20%5Capprox%20%5Cboxed%7B1.29%7D)
Sin²t +cos²t =1
<span> x=2+3 sin t
sin t=(x-2)/3
</span><span>y=1-1/2cos t
y-1= - (cos t)/2
cos t =-(y-1)/(1/2)
</span>(x-2)²/3² + (y-1)²/(1/2)² = 1
Ellipse
Answer:
i think its a
Step-by-step explanation:
